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3 years ago

angle A is a compliment of angle b and m angle b = (6-5x) degrees and m angle a =(7-2x)degrees find m angle a

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

A + B = 90

6 - 5x + 7 - 2x = 90

13 - 7x = 90

- 7x = 90 - 13

- 7x = 77

- x = 77 / 7

x = - 11

A: 6 - (5 * - 11) = 6 + 55 = 61

B: 7 - (2 * -11) = 7 + 22 = 29

Together they equal 90 as they should.

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Solve the system of linear equation 8X plus 5Y equals 18 and 6X plus Y equals -2 by using the linear Combination method Emmaus d

Hunter-Best [27]

$\text{The solution is } x = \frac{-14}{11} \text{ and } y = \frac{62}{11}$

Solution:

Given system of equations are:

8x + 5y = 18 ------- eqn 1

6x + y = -2 -------- eqn 2

Multiply eqn 2 by -5

-30x -5y = 10 ----- eqn 3

Add eqn 1 and eqn 3 so that y terms gets eliminated

8x + 5y = 18

-30x -5y = 10

( + ) --------------

-22x = 28

Divide both sides by -22

$x = \frac{28}{-22}\\\\x = \frac{-14}{11}$

Substitute the x value in eqn 1

$8(\frac{-14}{11}) + 5y = 18\\\\\frac{-112}{11} + 5y = 18\\\\5y = 18 + \frac{112}{11}\\\\5y = \frac{310}{11}\\\\y = \frac{62}{11}$

$\text{Thus the solution is } x = \frac{-14}{11} \text{ and } y = \frac{62}{11}$

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Step-by-step explanation:

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Answer:

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They are not linear equations because they are not written in the form

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kupik [55]

Answer:

$(a)\ T_{a,b} =(x +a,y+b)$

$(b)\ F_{y\ axis} = (-x,y)$

$(c)\ F_{x\ axis} = (x,-y)$

$(d)\ R_{o,90^o} = (-y,x)$

$(e)\ R_{o,180^o} = (-x,-y)$

$(f)\ R_{o,270^o} = (y,-x)$

Step-by-step explanation:

Solving (a): Translate a units right, b units up

When a function is translated a units right, the number of units will be added to the x coordinate

When a function is translated b units up, the number of units will be added to the y coordinate.

So, we have:

$T_{a,b} =(x +a,y+b)$

Solving (b): Reflect across y-axis

When a function is translated across the y-axis, the x coordinate gets negated.

So, we have:

$F_{y\ axis} = (-x,y)$

Solving (c): Reflect across x-axis

When a function is translated across the x-axis, the y coordinate gets negated.

So, we have:

$F_{x\ axis} = (x,-y)$

Solving (d): 90 degrees rotation counterclockwise

When a function is rotated 90 degrees counterclockwise, the y-coordinates gets negated and then swapped with the x-coordinate.

So, we have:

$R_{o,90^o} = (-y,x)$

Solving (e): 180 degrees rotation counterclockwise

When a function is rotated 180 degrees counterclockwise, the coordinates are negated.

So, we have:

$R_{o,180^o} = (-x,-y)$

Solving (f): 270 degrees rotation counterclockwise

When a function is rotated 270 degrees counterclockwise, the x-coordinates gets negated and then swapped with the y-coordinate.

So, we have:

$R_{o,270^o} = (y,-x)$

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