x
---- = 5 (solve for x)
0.6
x = 5(0.6)
x = 3
then....
3
----- = 15
0.2
your answer should be 15 ft per second.
hope this helps :)
Answer:
Percentage of computers working equals:
90%
Step-by-step explanation:
Three of the thirty computers are out of service.
Number of computers working=30-3=27
Total computers=30
Percentage of working computers=
=
= 90%
Hence, Percentage of computers working is:
90%
N = 273
273 / 7 = 39
Dividend / divisor = quotient
Work Backwards:
n/7 = 39
n = 39 X 7
n = 273
7 apples are red because 13-6=7
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
