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3 years ago

14

given 2 parallel lines and a transversal that intersects both parallel lines what must be true about pairs of corresponding angl

es

1 answer:

Phantasy [73]3 years ago

3 0

If two parallel lines are cut by a transversal, the corresponding angles are congruent.

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On a number line, the surface of a river is marked at −220 feet and the top of a building is marked at +19 feet, where 0 represe

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A

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0 is sea lvl so just add and subsubtract

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A circle and a square can intersect in a)two triangles b) four acrs c) one line d) eight points

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Find the slope of the line passing through the points (5,7) and (-4,2).

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Your answer is A!

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In the month of June, the temperature in Johannesburg, South Africa, varies over the day in a periodic way that can be modeled a

Art [367]

Answer:

The answer is " $\bold{T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5}$ "

Step-by-step explanation:

Given value:

Temp-maximum= $18^{\circ}$

Temp. minimum = $3^{\circ}$

It is halfway between 10 am and 10 pm to 4 am.

The sinus and cosine roles could be used throughout the year to predict fluctuations in climate models. Its type of formula that can be used to model such information is:

$T = A \cos B(t-C) + D,$ where parameters are A, B , C, D, T is the ° C temperature and t is the time (1-24)

$A = amplitude = \frac{(T_{max} - T_{min})}{2}\\\\$

$= \frac{(3 - 18)}{2}\\\\= - \frac{15}{2}\\\\ = -7.5$

$B = \frac{2 \pi}{24}\\\\$

$= \frac{\pi}{12}$

$C = \text{ units translated to the right}= 4$

$D = y_{min} + amplitude = units \ translated \ up\\\\$

D = 7.5 + 3 = 10.5

Its trigonometric function equation that model temperature T hours after midnight in Johannesburg t.

$T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5$

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4 years ago

Square area of 1150mm^2

kirill [66]

33.91 is the square area of your question

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3 years ago