Question

We're planning to enclose a rectangular field with fencing, and we know that for whatever reason we want the field to be 50 feet square. We also know that the field's width should be 23 feet longer than the field's length. What are the field's dimensions?

Answer 1

Answer:

$? \times \frac{?}{?}$

d

Answer 2

Answer:

2 by 25 feet.

Step-by-step explanation:

Let L and W be the length and the widht of the field

we want W = L + 23 and W x L = 50

So

(L + 23) x L = 50

$L^2 + 23L = 50\\L^2+23L-50 =0\\(L+25)(L-2)=0\\L=-25 \text{ or } L = 2$

Since L must be positive then L =2 and W = 2 + 23 = 25.