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Snezhnost [94]
3 years ago
14

In this diagram, BAC~EDF. If the area of BAC=15 in2, what is the area of EDF? 4, 5.

Mathematics
1 answer:
lesya692 [45]3 years ago
5 0

Answer:

9.6 square inches.

Step-by-step explanation:

We are given that ΔBAC is similar to ΔEDF, and that the area of ΔBAC is 15 inches. And we want to determine the area of ΔDEF.

First, find the scale factor <em>k</em> from ΔBAC to ΔDEF:

\displaystyle 5 k = 4

Solve for the scale factor <em>k: </em>

<em />\displaystyle k = \frac{4}{5}<em />

<em />

Recall that to scale areas, we square the scale factor.

In other words, since the scale factor for sides from ΔBAC to ΔDEF is 4/5, the scale factor for its area will be (4/5)² or 16/25.

Hence, the area of ΔEDF is:

\displaystyle \Delta EDF = \frac{16}{25}\left(15\right) = 9.6\text{ in}^2

In conclusion, the area of ΔEDF is 9.6 square inches.

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Vika [28.1K]

Answer:

A. 60°

Step-by-step explanation:

There's a very straight-forward explanation for this, thank god! XD

For this type of problem, there's a rule to follow for the outside angle. X and 120 should equal 180, so all you need to do is fill that gap.

180-120 = 60

60 is your answer because it completes the whole angle.

4 0
3 years ago
You have been asked to develop a composite measure of the quality of life on your campus.
Shkiper50 [21]

The social indicators that can be used to know the quality of life in campus are the number of hours spent in school, extra curricular activities, etc.

<h3>What are social indicators?</h3>

It should be noted that social indicators are used to monitor the social system.

The social indicators that can be used to know the quality of life in campus are the number of hours spent in school, extra curricular activities, etc. They're important to assess ones social life.

In conclusion, after necessary data has been collected m, a research can be made to know how the quality of life is affected by the data.

Learn more about indicators on:

brainly.com/question/485822

5 0
2 years ago
the legs of a right triangle are 4 units and 7 units. What is the length of the hypotenuse? Select one: a. square root 33 units
Mrac [35]

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{4^2+7^2}\implies c=\sqrt{65}

4 0
3 years ago
Read 2 more answers
Find x. (Use pic for more info)
V125BC [204]

Answer:

x=75

Step-by-step explanation:

Hey There!

If you didn't know the exterior angle of a triangle is equal to the sum of the opposite interior angles of a triangle

So essentially what I'm saying is that

2x-5=70+x

step 1 add 5 to each side

-5+5 cancels out

70+5=75

now we have

2x=70+x

step 2 subtract x from each side

x-x cancels out

2x-x=x

we're left with

x=75

8 0
3 years ago
ASAP I NEED HELP
alexdok [17]

The vertex of this parabola is at (3,-2). When the x-value is 4, the y-value is 3: (4,3) is a point on the parabola. Let's use the standard equation of a parabola in vertex form:

y-k = a(x-h)^2, where (h,k) is the vertex (here (3,-2)) and (x,y): (4,3) is another point on the parabola. Since (3,-2) is the lowest point of the parabola, and (4,3) is thus higher up, we know that the parabola opens up.

Substituting the given info into the equation y-k = a(x-h)^2, we get:

3-[-2] = a(4-3)^2, or 5 = a(1)^2. Thus, a = 5, and the equation of the parabola is

y+2 = 5(x-3)^2 The coefficient of the x^2 term is thus 5.

7 0
2 years ago
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