⚘<em>K</em><em>i</em><em>n</em><em>d</em><em>l</em><em>y</em><em> </em><em>r</em><em>e</em><em>f</em><em>e</em><em>r</em><em> </em><em>t</em><em>o</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>a</em><em>t</em><em>t</em><em>a</em><em>c</em><em>h</em><em>m</em><em>e</em><em>n</em><em>t</em><em>s</em><em> </em><em>f</em><em>o</em><em>r</em><em> </em><em>c</em><em>o</em><em>m</em><em>p</em><em>l</em><em>e</em><em>t</em><em>e</em><em> </em><em>s</em><em>o</em><em>l</em><em>u</em><em>t</em><em>i</em><em>o</em><em>n</em><em>s</em><em>!</em><em>!</em><em>~</em>
Answer: Toby will pay $34.45.
Step-by-step explanation:
I did 60% of 52 and the 6.25% of 52 and added my answers together.
All reals is the answer.
Since y =-9 graph is way below the absolute value graph. Meaning that y value of modulus is greater than the constant graph.
So to solve this question, your goal is to find out how the way it is solved is not correct.
Your answer would be: On the third line, the student adds the 8 to both sides instead of subtracting. The way the initial equation is given is
y-(-8)=-6(x-2). After distributing the six, the student should make the 8 positive because subtracting a negative makes a positive. After solving, the equation should look like: y(+8)=-6x+12, so you would subtract the 8 from both sides instead of adding it, and solve from there.
1.) D
2.) D
3.) C
4.) C
5.) 56 and 90 I looked for the pattern and followed it.
Get someone else to do 6 I cant
