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Firdavs [7]
3 years ago
7

What is corresponding angle? give a definition of it​

Mathematics
2 answers:
STatiana [176]3 years ago
7 0

Answer:

any pair of angles each of which is on the same side of one of two lines cut by a transversal and on the same side of the transversal.

<h2><em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>helpful</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em></h2>

<em><u>have</u></em><em><u> </u></em><em><u>nice</u></em><em><u> </u></em><em><u>day</u></em>

Alchen [17]3 years ago
5 0

Answer:

any pair of angles each of which is on the same side of one of two lines cut by a transversal and on the same side of the transversal.

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Jill is factoring the expression 13XY -52y. Her work is shown below
Sunny_sXe [5.5K]

Answer:13y(x-4)

Step-by-step explanation:

13xy-52y =13y(x-4)

3 0
3 years ago
The quotient of 5 plus d and 12 minus w
aev [14]
That expression is written like so:

(5 + d)/(12 - w)
6 0
3 years ago
In February, Alec had 1,562 visitors to his website. In March, he had 1,310 visitors to his website. What is the percentage decr
tigry1 [53]

Answer:

16.1% is the percentage decrease.

Step-by-step explanation:

We are given the following in the question:

Visitors in February = 1,562

Visitors in march = 1,310

We have to find the percentage decrease of the number of visitors to Alec's website from February to March.

Percentage decrease =

=\dfrac{\text{Change}}{\text{Original}}\times 100\%\\\\=\dfrac{1562-1310}{1562}\times 100\%\\\\=\dfrac{252}{1562}\times 100\% = 16.1\%

Thus, 16.1% is the percentage decrease in the number of visitors to Alec's website from February to March.

6 0
3 years ago
If 9 out of 20 candies are orange, how many orange candies will there be per 100 candies total?
avanturin [10]

Answer:

45

Step-by-step explanation:

20 / 9 = 2.222222222223

100 / 45 = 2.222222222223

9 is 45% of 20 and 45 is 45% of 100.

5 0
2 years ago
Please answer my question .q bo 4 d and e
sdas [7]
4 (e) 
sin^8 x - cos^8 x
= (sin^4 x + cos^4 x)(sin^4 x - cos^4 x)
= (sin^4 x + cos^4 x)(sin^2 x - cos^2x)(sin^2 x +cos^2 x)
=  (sin^4x + cos^4 x)( sin^2 x- cos^2 x)

Sorry I cant do 4 (d).
5 0
3 years ago
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