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Step2247 [10]
3 years ago
11

Are these rational numbers

Mathematics
1 answer:
Sav [38]3 years ago
8 0
Yes and second no it is not
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Decide whether the expression has been simplified correctly.
Alexeev081 [22]

Answer:

No.

Step-by-step explanation:

According to the law of exponent:-

\displaystyle \large{( \frac{a}{b}) ^{m}   =  \frac{ {a}^{m} }{ {b}^{m} }  }

Therefore:-

\displaystyle \large{( \frac{a}{4} )^{5} =  \frac{ {a}^{5} }{ {4}^{5} }  }

6 0
3 years ago
PLZ HELP. which equation is a non proportional situation?
Llana [10]
I think the answer is b
4 0
3 years ago
(sqrt3-sqrt3i)^4
Ludmilka [50]

The increasing order of the complex numbers is (√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ =  (-1 + √3i)¹² < (√3 - √3i)⁴.

<h3>Absolute values of the complex numbers</h3>

The absolute values of the complex numbers are determined as follows;

(sqrt3-sqrt3i)^4 = (√3 - √3i)⁴

|z| = \sqrt{(\sqrt{3} )^2 + (\sqrt{3 }\times1 )^2} } \\\\|z| = \sqrt{6}

(-1+sqrt3i)^12 = (-1 + √3i)¹²

|z| = \sqrt{(-1)^2 + (\sqrt{3)^2} } \\\\|z| = \sqrt{4} \\\\|z| = 2

(sqrt 3-i)^6 = (√3 - i)⁶

|z| = \sqrt{(\sqrt{3})^2 + (-1)^2 } \\\\|z| = \sqrt{4} \\\\|z| = 2

(sqrt2-sqrt2i)^8 = (√2 - √2i)⁸

|z| = \sqrt{(\sqrt{2} )^2 + (\sqrt{2})^2 } \\\\|z| = 2

(sqrt2-i)^6 = (√2 - i)⁶

|z| = \sqrt{(\sqrt{2})^2 + (-1)^2} } \\\\|z| = \sqrt{3}

Increasing order of the complex numbers;

(√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ =  (-1 + √3i)¹² < (√3 - √3i)⁴.

Learn more about complex numbers here: brainly.com/question/10662770

#SPJ1

3 0
2 years ago
Can someone please answer this question?
Verdich [7]

100 because sum means addition so 1+0+0 is one, and one X one hundred is 100

Hope this helps :D

5 0
3 years ago
I only have one question left please help?????!?
NemiM [27]
Option 4 would be the correct answer
7 0
3 years ago
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