(2m + 3)(m^2 - 2m + 1) =
2m(m^2 - 2m + 1) + 3(m^2 - 2m + 1) =
2m^3 - 4m^2 + 2m + 3m^2 - 6m + 3 =
2m^3 -m^2 - 4m + 3 <===
Answer:
Since Tracy is charged $29 for 250 free minutes so:
For x ≤ 250, f(x) = $29
tracy is charged an extra $0.35 per minute for calls over 250 minutes, so:
For x ≥ 250, f(x) = 29 + 0.35(x - 250)
Machine J's equation would be 30x=y. To find out how many more candies Machine J packets, You would plug in 11 as x and you would get 330.
For Machine K, you would just plug in 11 as x. Your answer is 286.
Now you would subtract. 330-286=44.
Answer:
=53*(54 ×^9 y^12 z^15)^1/2
=53*y^6 *z^(15/2) * x^( 9/2)* (54)^1/2
