What are the zeros of f(x)=x^2-12+36
1 answer:
Answer:
x = 6
Step-by-step explanation:
I think it's supposed to be
y = x² - 12x + 36
Set the equation equal to zero and solve...
0 = x² - 12x + 36
Now factor. What 2 numbers add to -12, and multiply to 36?
-6 and -6, so our factors are
0 = (x - 6)(x - 6)
So
0 = x - 6, then
6 = x
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