Use the distance formula to find the value of the side lengths.
d=√((x1-x2)²+(y1-y2)²
d of side AC is 6
d of side CB is 10
Angela's use of the Pythagorean Theorem of 10²+6²+c² is incorrect; she put the right values in the wrong spots, the formula needed is:
6²+10²=c²
Option C- Angelica's side lengths were too long.
Answer:
- (2x + 5)/(x - 9)
- 3. quantity 2 x plus 5 over x minus 9
Step-by-step explanation:
Quantity 2 x squared plus 13 x plus 20 all over x squared minus 5 x minus 36
- (2x² + 13x + 20)/(x² -5x - 36) =
- (2x²+ 5x + 8x + 20)/(x² - 9x + 4x -36)=
- (2x + 5)(x + 4)/(x - 9)(x + 4) =
- (2x + 5)/(x - 9)
Correct option is option 3
D) f(n) = 3 + 4(n-1)
3 = 1st term
4 = common difference among the terms
n = term number you are looking for.
To check: 3, 7, 11, 15, ...
f(1) = 3 + 4(1-1) = 3 + 4(0) = 3 + 0 = 3
f(2) = 3 + 4(2-1) = 3 + 4(1) = 3 + 4 = 7
f(3) = 3 + 4(3-1) = 3 + 4(2) = 3 + 8 = 11
f(4) = 3 + 4(4-1) = 3 + 4(3) = 3 + 12 = 15
A would be the correct ans
