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Sliva [168]
3 years ago
13

PLZ EXPLAIN AND I'LL GIVE BRAINLY!!!!

Mathematics
1 answer:
Nonamiya [84]3 years ago
7 0

Hello there!

Given the sequence:

\displaystyle \large{ 1, - 3,9, - 27,...}

The question reveals it to be geometric sequence since it has common ratio.

<u>G</u><u>e</u><u>o</u><u>m</u><u>e</u><u>t</u><u>r</u><u>i</u><u>c</u><u> </u><u>S</u><u>e</u><u>q</u><u>u</u><u>e</u><u>n</u><u>c</u><u>e</u> / <u>R</u><u>a</u><u>t</u><u>i</u><u>o</u><u> </u><u>F</u><u>o</u><u>r</u><u>m</u><u>u</u><u>l</u><u>a</u>

<u>\displaystyle \large{r =  \frac{a_{n + 1}}{a_n} }</u>

Define 'r' as common ratio.

First, let's check the common ratio by using the formula above.

<u>R</u><u>a</u><u>t</u><u>i</u><u>o</u><u> </u><u>C</u><u>h</u><u>e</u><u>c</u><u>k</u>

\displaystyle \large{r =  \frac{ - 3}{1} \longrightarrow  - 3 } \\  \displaystyle \large{r =  \frac{ 9}{ - 3} \longrightarrow  - 3 } \\  \displaystyle \large{r =  \frac{ - 27}{9} \longrightarrow  - 3 }

Therefore, the common ratio or r-value is -3.

To find the 7th term of sequence, you can by using the General Geometric Terms.

<u>G</u><u>e</u><u>n</u><u>e</u><u>r</u><u>a</u><u>l</u><u> </u><u>T</u><u>e</u><u>r</u><u>m</u><u> </u><u>o</u><u>f</u><u> </u><u>G</u><u>e</u><u>o</u><u>m</u><u>e</u><u>t</u><u>r</u><u>i</u><u>c</u>

\displaystyle \large{a_n = a_1 {r}^{n - 1} }

a1 is defined as the first term of sequence.

r is common ratio.

n is the term.

Since we want to find 7th term:

  • a1 = 1
  • r = -3
  • n = 7

\displaystyle \large{a_7 =1{( - 3)}^{7 - 1} } \\  \displaystyle \large{a_7 =1{( - 3)}^{6} } \\  \displaystyle \large{a_7 =729 }

Therefore, the 7th term of this sequence is 729.

Let me know if you have any questions!

Topic: Sequence and Series / Geometric Sequence

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