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kap26 [50]
3 years ago
8

Least to greatest 7.0, 0.07, 0.7, 0.077

Mathematics
1 answer:
forsale [732]3 years ago
6 0

Answer:

0.07

0.077

0.7

7.0

is correct form of least to great

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Rudy collects baseball cards, and he currently has 300 cards. Starting tomorrow, he will purchase 1 pack of 15 baseball cards ev
Delvig [45]

Answer:

To find the number of cards, you must use the equation c = 300 + 17d. Collecting your known information in an organized form will be realllly helpful now and in the future. C represents the number of cards, while D represents the number of days!

Step-by-step explanation:

Starting with the original amount, which is 300---->

Here is the answer:

15 - 1 + 3 = 17 extra cards per day

3 0
4 years ago
Solve.<br> 4(y + 4) = 32
MakcuM [25]

Answer:

y = 4

Step-by-step explanation:

4*y = 4y

4*4 = 16

4y+16=32

to get 4y alone, we subtract 16 from 32.

32-16 = 16

4y = 16

to get y alone, we divide 4 by 16

16/ 4 = 4

so, y = 4

8 0
3 years ago
Read 2 more answers
Sam makes x dollars an hour. Every hour she loses 3 dollars in taxes. After five hours, she has 70 dollars in total. How much do
Triss [41]
85 USD FOR 5 HOURS

17 USD FOR 1 HOUR


HOPE I HELPED YOU TODAY
8 0
4 years ago
the mass of a certain grain of rice is about 3 x 10^-2 grams. The mass of a certain grain of salt is about 6 x 10^-5 grams.
lina2011 [118]

Answer:

Step-by-step explanation:

Rice: 3 x 10^-2 = 0.03 grams

Salt: 6 x 10^-5 = 6e-5 grams

4 0
3 years ago
How do I do 8b(ii) ? Please help me thank you!
Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


7 0
3 years ago
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