Question

What are the solutions for x when y is equal to 0 in the following quadratic

Answer 1

Answer:

The correct answer option is E) No solution.

Step-by-step explanation:

We are given the following quadratic equation which we are to solve for x when the value of y is 0:

$y = x ^2+ 6x +12$

$x ^2+ 6x +12=0$

Using the quadratic formula since there are no factors:

$x=\frac{-b \pm \sqrt{b^2-4ac }}{2a}$

Substituting the values in the formula to get:

$x=\frac{-6 \pm \sqrt{6^2-4(1)(12) }}{2(1)}$

$x=-3+\sqrt{3}i$ or $x=-3-\sqrt{3}i$

There are no real number solutions to this quadratic equation.