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Lubov Fominskaja [6]
3 years ago
11

What are the solutions for x when y is equal to 0 in the following quadratic

Mathematics
1 answer:
navik [9.2K]3 years ago
6 0

<u>Answer:</u>

The correct answer option is E) No solution.

<u>Step-by-step explanation:</u>

We are given the following quadratic equation which we are to solve for x when the value of y is 0:

y = x ^2+ 6x +12

x ^2+ 6x +12=0

Using the quadratic formula since there are no factors:

x=\frac{-b \pm \sqrt{b^2-4ac }}{2a}

Substituting the values in the formula to get:

x=\frac{-6 \pm \sqrt{6^2-4(1)(12) }}{2(1)}

x=-3+\sqrt{3}i or x=-3-\sqrt{3}i

There are no real number solutions to this quadratic equation.

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If the figure is reflected over the line y=x, which rule is true
saveliy_v [14]

Answer:

These reflected points represent the inverse function

Step-by-step explanation:

This is just one of the rules that are true.

8 0
3 years ago
Point Y is in the interior of ∠XWZ. Given that WX→ and WZ→ are are opposite rays, and m∠XWY=4(m∠YWZ) is m∠YWZ?.
EleoNora [17]

Answer:

m∠YWZ=36°

Step-by-step explanation:

Opposite rays are two rays that both start from a common point and go off in exactly opposite directions. Because of this the two rays (WX and WZ) form a single straight line through the common endpoint W.

If rays WX and WZ are opposite, then angle XWZ is straight angle. A straight angle always has the measure of 180°.

Point Y is in the interior of ∠XWZ, then angles XWY and EWZ are supplementary angles (together form straight angle XWZ). Supplementary angles always add up to 180°, then

m∠XWY+m∠YWZ=180°

You are given that

m∠XWY=4(m∠YWZ).

Substitute it into the previous equality:

4(m∠YWZ)+m\angle YWZ=180°

5(m∠YWZ)=180°

m∠YWZ=36°

5 0
3 years ago
14m + 51 - 6s + 75 - 81 + 115 - 95 - 41 + 10p - 3p + 51<br> what is the coefficient of m?
densk [106]

Answer:

14is \: coefficient \: of \: m

4 0
2 years ago
For each function below, determine whether or not the function is injective and whether or not the function is surjective. (You
Harlamova29_29 [7]

Answer: First, injective means that for every y, there is only one x such f(x) = y, and surjective means that if f is a function that goes from the set {x} to the set {y}, for every element y in the codomain there is at least one element x in the domain such f(x) = y

(a) f:R----> + R given by f(x) = x2 (i guess you written x^{2})

The function is not injective, because f(-2) = f(2), and is surjective, because the codomain is +R, and x^{2} is always a positive real number.

(b) f:N----> + N given by f(n) = n2  (i guess you written n^{2})

As the naturals have no negative numbers, in this case the function is injective, but isn't surjective, because there is no number that when squared is equal to 5, for example.

(c) f: Zx Z → Z given by f(n, k) = n +k:

here the domain is of the form (n,k) and the function is n +k, so the numbers (z,w) and (w,z) return the same value when evaluated in f, then f is not injective. And is easy to see that f is surjective, because in the sum you can reach al the integers on the codomain.

3 0
3 years ago
Given y=3x-7. When x = 0 what is the value of y
MissTica

Answer:

-7

Step-by-step explanation:

y=3x-7

x=0 ⇒ y= 3*0-7= -7

7 0
3 years ago
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