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Butoxors [25]
3 years ago
8

The assositive property works with expressions that use

Mathematics
2 answers:
damaskus [11]3 years ago
5 0

Answer:

The associative property can be used with multiplication and addition.

Examples:

2+(3+2) -> (2+3)+2 (Associative Addition)

2*(3*2) -> (2*3)*2 (Associative Mult.)

It does not work with division or subtraction.

2-(3-2) does not equal (2-3)-2

JulijaS [17]3 years ago
4 0

Answer:

lol

Step-by-step explanation:

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Hi there
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3 years ago
Garne Problem med
Citrus2011 [14]

Total distance the rover need to travel ​is D = 1miles .

<u>Step-by-step explanation:</u>

We have , Garne Problem med   . A rover needs to travel mile to reach its destination  traveled mile. a rover needs to travel 5/8 mile to reach its destination it has already travel 3/8 miles . We need to find that  how much farther does the rover need to travel ​ , Let's do it step by step:

First , rover has already traveled 3/8 miles , Let total distance to be traveled by rover is D :

⇒ D = \frac{3}{8} + d , where d is distance left to cover .

Now, rover need to travel 5/8 miles more to reach destination :

⇒ D = \frac{3}{8} + d , where d is distance left to cover  , So d = \frac{5}{8}

⇒ D = \frac{3}{8} + d

⇒ D = \frac{3}{8} + \frac{5}{8}

⇒ D = \frac{3+5}{8}

⇒ D = \frac{8}{8}

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8 0
3 years ago
Assume we cut the last piece of the pie into two sections (1 and 2) along ray BD
earnstyle [38]

Answer:

If we want the greatest portion of pie, then you must choose the section with the greatest angle. Therefore, we must choose Section 2. But if we want the smallest portion of pie, then we must choose Section 1.

Step-by-step explanation:

From statement, we know that measure of the angle ABC is equal to the sum of measures of angles ABD (<em>section 1</em>) and DBC (<em>section 2</em>), that is to say:

m \angle ABC = m\angle ABD + m\angle DBC (1)

If we know that m\angle ABC = 40^{\circ}, m\angle ABD = 2\cdot x + 3 and m\angle DBC = 4\cdot x + 7, then the value of x is:

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x = 5

Then, we check the angles of each section:

Section 1

m\angle ABD = 2\cdot x + 3

m\angle ABD = 13^{\circ}

Section 2

m\angle DBC = 4\cdot x + 7

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If we want the greatest portion of pie, then you must choose the section with the greatest angle. Therefore, we must choose Section 2. But if we want the smallest portion of pie, then we must choose Section 1.

6 0
3 years ago
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