EASYY pls help asappppppppppppp

In a randomly selected sample of 1169 men ages 35–44, the mean total cholesterol level was 210 milligrams per deciliter with a s

Aneli [31]

Answer:

The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 210, \sigma = 38.6$

Find the highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10%.

This is the 10th percentile, which is X when Z has a pvalue of 0.1. So X when Z = -1.28.

$Z = \frac{X - \mu}{\sigma}$

$-1.28 = \frac{X - 210}{38.6}$

$X - 210 = -1.28*38.6$

$X = 160.59$

The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.

5 0

3 years ago

The graph represents the normal distribution of recorded weights, in pounds, of cats at a veterinary clinic.

diamong [38]

Answer:

B) 8.9 lbs

C) 9.5 lbs

D) 9.8 lbs

E) 10.4 lbs

Step-by-step explanation:

From the graph, 9.5 is the mean of the sample and 0.5 is the standard deviation of the sample.

As we have to find the weights that lie within the 2 standard deviations of the mean i.e

$=9.5\pm 2(0.5)$

$=8.5,10.5$

Among the given weights only 8.9 lbs, 9.5 lbs, 9.8 lbs, 10.4 lbs will lie within 2 standard deviations of the mean.

3 0

3 years ago

Read 2 more answers

2 3/4 divided by 1/2 ?

Vladimir [108]

Answer:

5.5

Step-by-step explanation:

7 0

2 years ago

In the table, x represents the age in years of a collectible baseball card, and y represents its value in dollars. Cost of a Pac

lukranit [14]

Answer:

b

Step-by-step explanation:

The slope is positive because as the age increases, the value increases.

6 0

3 years ago

Read 2 more answers

According to the Census Bureau, 3.39 people reside in the typical American household. A sample of 26 households in Arizona retir

Vikki [24]

Answer:

$t=\frac{2.73-3.39}{\frac{1.22}{\sqrt{26}}}=-2.758$

$df=n-1=26-1=25$

$p_v =P(t_{(25)}$

Since the p value is lower than the significance level 0.1 we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is significanlty lower than 3.39 personas at 10% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=2.73$ represent the sample mean

$s=1.22$ represent the sample standard deviation

$n=26$ sample size

$\mu_o =3.39$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is less than 3.39 persons, the system of hypothesis would be:

Null hypothesis: $\mu \geq 3.39$

Alternative hypothesis: $\mu < 3.39$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.73-3.39}{\frac{1.22}{\sqrt{26}}}=-2.758$

P-value

The degreed of freedom are given by:

$df=n-1=26-1=25$

Since is a one sided lower test the p value would be:

$p_v =P(t_{(25)}$

Conclusion

Since the p value is lower than the significance level 0.1 we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is significanlty lower than 3.39 personas at 10% of significance.

3 0

3 years ago