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raketka [301]
3 years ago
7

Prove this identify : 2 cos^2 (45°-A ) = 1 +sin 2 A​

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0
I wasn’t sure how to put this into words. I hope this makes sense. <3

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Two straight lines have equations y = p x + 4 y = p x + 4 and p y = q x − 7 p y = q x − 7 , where p p and q q are constants. The
kolbaska11 [484]

Answer:

q = \frac{8}{3}

Step-by-step explanation:

The point of intersection (3, 1 ) is the solution to both equations

Using

y = qx - 7 and substituting x = 3, y = 1

1 = 3q - 7 ( add 7 to both sides )

8 = 3q ( divide both sides by 3 )

\frac{8}{3} = q

6 0
3 years ago
Admission to the county fair costs $9 per person. The ride tickets cost $2.50 each.
maksim [4K]

Answer:$11.5

Step-by-step explanation:

Admission = $9 charged once

each ride = $2.5x (x=number of rides)

Total cost for x rides

=2.5x+9

7 0
2 years ago
How do I solve <br><br> 10x-3(7-2x)+18
kiruha [24]
10x-(3x7-3x2x)+18
10x-(21-3x2x)+18
10x-(21-6x)+18
10x-21+6x+18
16x-21+18
16x-3
8 0
3 years ago
Read 2 more answers
Calculate the missing angle and give a reason for your answer
Vanyuwa [196]

Step-by-step explanation:

the triangle is an isosceles triangle hence the base angles are equal

sum of angles in a triangle is 180°, therefore, the top angle =180-(62+62)

the top angle =56°

h°= the top angle because alternate angles are equal

hence, h=56°

5 0
3 years ago
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Triangle HIJ has been reflected to create triangle H'I'J'. Segment HJ= H'J'= 4, segments IJ = I'J' = 7, and angles J and J' are
svlad2 [7]
The postulate that prove that the two triangles in your problem is congruent is SAS or Side Angle Side postulate. This postulate is use when the given of an equation are only 2 side and an angle and also it gives the answer or the side on which the angle is projected. By means of that you can tell or figure out that the two triangle is congruent. So the answer is letter B. SAS
8 0
3 years ago
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