For the first one you need to do
x+2+x+2+2x+4+2x+4
=6x+12
When doing this kind of problem you should use FOIL
First, Outer, Inner, Last
(x+2)(2x+4)
First- x•2x= 2x^2
Outer- x•4= 4x
Inner- 2•2x= 4x
Last- 2•4= 8
Combined you have
=2x^2+8x+8
I believe it is 3. since it touches the x-axis in three areas
Q-2r=4, therefore: q=4+2r.
Plug the value of q into q+r=37, so you get:
4+2r+r=37
3r=37-4=33
3r=33
Therefore: r=11.
q-2r=4, but r=11, so:
q-2(11)=4
q-22=4
Therefore q=26.
Check if the answer is correct using second equation:
q=4+2r=4+2(11)=4+22=26.
So: q=26 and r=11.
Answer:
4/10, 0.4, 40%
1/4, 0.25, 25%
Hope this helps also "Hi" again. :)
