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8090 [49]
3 years ago
14

Jacqueline is checking her bicycle’s wheel. The wheel has a radius of 20 cm, and its center is 51 cm above the ground. Jacquelin

e is rotating the wheel at a constant speed of 225°/s. The height of a point on the tire as a function of time is given by h = 51 + 20 sin(225t), where h is the height in centimeters and t is the time in seconds. Find h when t = 19 s. Find your answer to the nearest tenth of a centimeter.
Mathematics
1 answer:
Alex777 [14]3 years ago
6 0

Answer:

h = 36.9 cm

Step-by-step explanation:

The function given to us is:

h(t) = 51 + 20 sin(225t)

Where h(t) is the function of the height in centimeters while t represents the time in seconds.

We have to find the height h(t) when the time is equal to 19 seconds.

Substitute t=19 into the given function

h(19) = 51 + 20 sin(225(19))

h(19) = 51 + 20 sin(4275)

h(19) = 51 + 20 (-0.7071)

h(19) = 51 + (-14,1421)

h(19) = 36.8579 cm

Rounding off to nearest 10th

h = 36.9 cm

You might be interested in
What is the volume of this cylinder? *
Juli2301 [7.4K]

Answer   V≈351.86

Step-by-step explanation: V=πr2h=π·42·7≈351.85838

The formula for the volume of a cylinder is V=Bh  or  V=πr2h .

The radius of the cylinder is 4 cm and the height is 7 cm.

Substitute 4 for r and 7 for h in the formula V=πr2h .

V= pie (4)² (7)

v= pie ( 14) (49)

5 0
2 years ago
Question 13
Mrac [35]

Answer:

71.6 degrees

Step-by-step explanation:

Given the vectors

u= <8,4> v = <9.-9> (5 points)

u*v = (8, 4)*(9, -9)

u*v = 8(9)+(4)(-9)

u*v = 72 - 36

u*v = 36

|u| = √8²+4²

|u| = √64+16

|u| = √80

|v| = √9²+9²

|v|  = √81+81

|v|  = √162

Using the formula

u*v = ||u||v| cos theta

36 = √80(√162)cos theta

36 = √12960 cos theta

cos theta = 36/√12960

cos theta = 36/113.8

cos theta = 0.3162

theta = arccos(0.3162)

theta = 71.56 degrees

Hence the angle between the given vectors to the nearest tenth of a

degree is 71.6 degrees

5 0
2 years ago
a person Can travel 120 miles in one direction. the return trip was accomplished at double the speed and took three hours less t
BaLLatris [955]
40 mph would be 120 miles in 3 hours (120/40)

80 mph is 120 miles in 1.5 hours(120/80)

3 - 1.5 = 1.5, not 3 hrs

Change the speed to 20 mph( 1/2 the speed) to double the hours.

20 mph = 6 hours(120/20)

40 mph = 3 hrs(120/40)

6 - 3 = 3 hours difference
6 0
3 years ago
Please anyone solve this for me..No spam.​
Tamiku [17]

Answer:

  • 3096

Step-by-step explanation:

<u>Given:</u>

  • 3x-\frac{1}{4y}=24

<u>Rewrite it as:</u>

  • 3x=\frac{1}{4y}+24
  • x=\frac{1}{12y}+8

<u>Simplify the expression:</u>

  • 8x(6x - \frac{1}{y} ) + \frac{1}{12y^2} (4 - 3y + 36xy^2) =
  • 8(\frac{1}{12y}+8)(6(\frac{1}{12y}+8) - \frac{1}{y} ) + \frac{1}{3y^2}  - \frac{1}{4y}  + 3x =
  • 8(\frac{1}{12y}+8)(48- \frac{1}{2y} ) + \frac{1}{3y^2}  - \frac{1}{4y}  + 24 + \frac{1}{4y}  =
  • 8(\frac{4}{y}+8*48- \frac{1}{24y^2} -\frac{4}{y} ) + \frac{1}{3y^2}  + 24  =
  • 8(384-\frac{1}{24y^2}) + \frac{1}{3y^2}  + 24  =
  • 8*384-\frac{1}{3y^2} + \frac{1}{3y^2}  + 24  =
  • 3072+24=
  • 3096
3 0
2 years ago
You have a 1200-foot roll of fencing and a large field. you want to make two paddocks by splitting a rectangular enclosure in ha
romanna [79]
Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change  w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
8 0
3 years ago
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