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3 years ago

What is the area of a circle, rounded to the nearest tenth, with a diameter of 12 centimeters?

Mathematics

1 answer:

inessss [21]3 years ago

3 0

Answer:

113

Step-by-step explanation:

area of a circle is 3.14*r^2

r=d/2 r=6

3.14*36=113

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Can ya'll answer this question?

diamong [38]

The third fin is the answer.

3 0

3 years ago

If a+b+c =0 show that a³+b³+c³= 3abc

slega [8]

Answer:

Step-by-step explanation:

a+b+c=0, a+b=-c,a+c=-b, b+c=-a

(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=

a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=

a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=

a^3+b^3+c^3+3a^2*(-a)+3c^2*(-c)+3b^2*(-b)+6abc=

a^3+b^3+c^3-3a^3-3c^3-3b^3+6abc=

6abc-2a^3-2b^3-2c^3=2(3abc-a^3-b^3-c^3)=

2*[3abc-(a^3+b^3+c^3)]=0

so 3abc-(a^3+b^3+c^3)=0

so a^3+b^3+c^3=3abc

7 0

3 years ago

Help I'll give you 100 points

Dvinal [7]

✏ Answer:

$y=-9$

Step-by-step explanation:

$2-\frac{1}{8}y=11+\frac{7}{8}y$

➠ Subtract 2 from both sides:-

 $2-\frac{1}{8}y-2=11+\frac{7}{8}y-2$

$-\frac{1}{8}y=\frac{7}{8}y+9$

➠ Subtract 7/8y from both sides:-

 $-\frac{1}{8}y-\frac{7}{8}y=\frac{7}{8}y+9-\frac{7}{8}y$

$-y=9$

➠ Divide both sides by -1:-

 $\frac{-y}{-1}=\frac{9}{-1}$

$y=-9$

OAmalOHopeO

✎--------------------------

7 0

2 years ago

Read 2 more answers

PLZ HELP WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST What is the slope-intercept form of the equation of the line that passes

grigory [225]

Answer:

Step-by-step explanation:

We are given the two points (2,7) and (4,-1). In order to determine the linear equation, we need to find the slope and the y-intercept. First, find the slope m. Let (2,7) be x1 and y1, and let (4,-1) be x2 and y2:

$m=\frac{y_2-y_1}{x_2-x_1} =\frac{-1-7}{4-2}=-8/2=-4$