That is a decrease of 78 ounces
Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:


Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:


Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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Answer:

Step-by-step explanation:
In left small right triangle: we have the square of left side = 5^2 + y^2 = 25 + y^2
In right small right triangle: we have the square of right side = 8^2 + y^2 = 64 + y^2
In the large right triangle, we have (25 + y^2) + (64 + y^2) = (5 + 8)^2
89 + 2y^2 = 13^2 = 169
2y^2 = 169 - 89 = 80
y = 80/2 = 40
so
