Answer:
(2,4)
Step-by-step explanation:
We have the system:
y=x+2
y=3x-2.
This is already setup for substitution.
I'm going to replace my first y with what the second y equals.
That is, I'm going to write 3x-2=x+2.
Time to solve the following for x:
3x-2=x+2
Subtract x on both sides:
2x-2= 2
Add 2 on both sides:
2x. = 4
Divide both sides by 2:
x. = 2
Now that we know x=2 and we have an equation that relates x to y: either y=x+2 or y=3x-2, doesn't matter which we use, we can find y.
So we y=x+2 with x=2 which means y=2+2=4.
So the solution, the intersection, is (2,4).
It's kinda blurry. I'm sorry!!
It’s wether dividing or multiplying
Answer:
That will be;
3x^2 + 5x -6 = 0
Step-by-step explanation:
Here, we want to write 3x^2 + 5x = 6 in the form
ax^2 + bx + c = 0
That will be;
3x^2 + 5x -6 = 0
We can simply get it by bringing the value 6 from the right hand side of the equation to the left hand side of the equation
