All categories

3 years ago

Write the number 10 000 000 as a power of 10.

Mathematics

1 answer:

geniusboy [140]3 years ago

4 0

Answer:

10⁷

Step-by-step explanation:

Just count the number of zero and raise the counted number of zero.

You might be interested in

Ugh idkplease help ASAP

Travka [436]

12/23 = 0.5217 = 52%

7 0

3 years ago

For the function f(x) = 7/2x-16, what is the difference quotient for all nonzero values of h?

sergey [27]

Answer:

$\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}$

Step-by-step explanation:

Given

$f(x) = \frac{7}{2}x - 16$

Required

The difference quotient for h

The difference quotient is calculated as:

$\frac{f(x + h) - f(x)}{ h}$

Calculate f(x + h)

$f(x) = \frac{7}{2}x - 16$

$f(x+h) = \frac{7}{2}(x+h) - 16$

$f(x+h) = \frac{7}{2}x+ \frac{7}{2}h- 16$

The numerator of $\frac{f(x + h) - f(x)}{ h}$ is:

$f(x + h) - f(x) = \frac{7}{2}x+ \frac{7}{2}h- 16 -(\frac{7}{2}x - 16)$

$f(x + h) - f(x) = \frac{7}{2}x+ \frac{7}{2}h- 16 -\frac{7}{2}x + 16$

Collect like terms

$f(x + h) - f(x) = \frac{7}{2}x -\frac{7}{2}x + \frac{7}{2}h- 16 + 16$

$f(x + h) - f(x) = \frac{7}{2}h$

So, we have:

$\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}h \div h$

Rewrite as:

$\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}h * \frac{1}{h}$

$\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}$

5 0

3 years ago

HELP ASAP! Which is the steepest slope?<br> A. -3 <br>B. 1 <br>C. 2 <br>D. -4

olga55 [171]

Positive and negative doesn’t matter. Steepest slope is the smallest or largest number.
In this case D. -4

3 0

3 years ago

Analyze the diagram below and complete the instructions that follow.

Kamila [148]

I think the ans is 10

7 0

3 years ago

If f(3) = 3^x and g(x) = 7^x then the graph of g(x) will be — the graph of f(x) when x<0.

Allushta [10]

Using the given exponential functions, it is found that the graph of g(x) will be less than than the graph of f(x) when x < 0.

<h3>What are the exponential functions?</h3>

The given exponential functions, f(x) and g(x), are respectively given by:

$f(x) = 3^x$

$g(x) = 7^x$

When x < 0, one possible value is x = -1, hence evaluating the functions at these values:

$f(-1) = 3^{-1} = \frac{1}{3}$

$g(-1) = 7^{-1} = \frac{1}{7}$

$\frac{1}{3} > \frac{1}{7}$ , hence, the graph of g(x) will be less than than the graph of f(x) when x < 0.

More can be learned about exponential functions at brainly.com/question/25537936

3 0

2 years ago