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tangare [24]
3 years ago
14

Robert bought a house with a 6 percent interest rate. Three months later, the rate dropped to 4.35 percent. Robert was frustrate

d that he bought his house at the wrong time. What type of risk does this BEST demonstrate? A. Income risk B. Interest rate risk C. Personal risk D. Inflation risk
Mathematics
1 answer:
docker41 [41]3 years ago
3 0

Answer:

b

Step-by-step explanation:

Interest rate risk is the risk that a fall in interest rate would decrease the value of a fixed rate investment. e.g. bonds , real estate.

Interest rate dropped 3 months after the house was bought. Robert is facing interest rate risk

Income risk is the risk that the stream of income received from a particular investment would drop as a result of a fall in interest rate.

Inflation risk is the risk that inflation would decrease the value of an investment

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.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and
Leni [432]

Answer:

a) Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

b) t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

Step-by-step explanation:

Information given

\bar X=130 represent the sample mean for the amount spent each shopper

s=40 represent the sample standard deviation

n=80 sample size  

\mu_o =120 represent the value to verify

t would represent the statistic    

p_v represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:  

Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

5 0
4 years ago
Daniela is 23 years older than her daughter. in 5 years, their ages will total 63. how old are they now?
pshichka [43]
Both their ages totaled in 5 (years) - 5 (years)

63 - 5 = 58

Current ages totaled = 58 (years)

Daniela is 23 years older than her daughter (as given above) so...

Current ages totaled (58 years) - How many years Daniela is older than her daughter ( 23 years )

58 - 23 = 35

So, Daniela’s age is currently 35 years and her daughter’s age would be 23 years.







6 0
3 years ago
Farmer Tom's chickens and sheets are in a jumble. He counts 48 heads and 134 legs, how many sheep does he have?
svetlana [45]
48=x+y
143= 2x+4y
y= sheep
48-y = x
143=2(48-y)+4y
143= 96-2y+4y
143=96+2y
47=2y
y=19
19 sheep
4 0
3 years ago
Read 2 more answers
5-2(a+3b)/2 When a=4 and b=1.
nirvana33 [79]

Hello macelynn190!

\huge \boxed{\mathfrak{Question} \downarrow}

\huge \tt \frac{5 - 2(a + 3b)}{2}

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

To solve this question we need to substitute the given values of 'a' & 'b' in the equation & then simplify it.

Given,

  • a = 4
  • b = 1

Now, substitute this in the place of 'a' & 'b'..

\large \tt \frac{5 - 2(a + 3b)}{2}  \\  =  \large   \underline{\underline{\tt \:  \frac{5 - 2((4) + 3(1))}{2} }}

Lastly, simplify it...

\large   \tt \:  \frac{5 - 2((4) + 3(1))}{2}  \\  =   \large \tt\frac{5 - 2(4 + 3)}{2}  \\  =  \large \tt \:  \frac{5 - 2(7)}{2}  \\  =  \large \tt \: \frac{5 - 14}{2}  \\  =  \large \tt\frac{-9}{2}  \\  = \large  \boxed{\boxed{  \bf \: -\frac{9}{2}=-4.5}}

  • The answer is <u>-</u><u>9</u><u>/</u><u>2</u><u> </u><u>or </u><u>-</u><u>4</u><u>.</u><u>5</u>

__________________

Hope it'll help you!

ℓu¢αzz ッ

5 0
3 years ago
Read 2 more answers
2 4/7 divided by 1 3/6 =
Rudiy27

Answer:

Step-by-step explanation:

2,57 divided by 1.5 equals

1.713

7 0
1 year ago
Read 2 more answers
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