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tangare [24]
2 years ago
14

Robert bought a house with a 6 percent interest rate. Three months later, the rate dropped to 4.35 percent. Robert was frustrate

d that he bought his house at the wrong time. What type of risk does this BEST demonstrate? A. Income risk B. Interest rate risk C. Personal risk D. Inflation risk
Mathematics
1 answer:
docker41 [41]2 years ago
3 0

Answer:

b

Step-by-step explanation:

Interest rate risk is the risk that a fall in interest rate would decrease the value of a fixed rate investment. e.g. bonds , real estate.

Interest rate dropped 3 months after the house was bought. Robert is facing interest rate risk

Income risk is the risk that the stream of income received from a particular investment would drop as a result of a fall in interest rate.

Inflation risk is the risk that inflation would decrease the value of an investment

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a train leaves from new york to chicago at 60mph. ANother train leaves from Chicago to New York at 40 mph. How far apary are the
Nutka1998 [239]

Answer:

100 miles

Step-by-step explanation:

Relative Speed: 60+40=100 mph

you can think that one train is stationary,another one is 100 mph

so one hour before the train pass each other,the distance is 100 miles

3 0
3 years ago
On a test, shelly got approximately 93% of the items correct. she got 76 questions right. how many questions were on the test? a
svetlana [45]
You multiply 76 by 0.93. That is 70.68 which rounds to 71. To check, (71/76) = ~93.
8 0
3 years ago
Amy, Bodie, Claire, and Dejan are in the same math class. The locations of their desks in relation to each other are graphed on
Xelga [282]

Answer:10 ft

Step-by-step explanation:

5 0
3 years ago
What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove
wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

  • \frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2

5b^3-10=6b^3-4b^2-10

\mathrm{Switch\:sides}

6b^3-4b^2-10=5b^3-10

6b^3-4b^2-10+10=5b^3-10+10

6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

b^3-4b^2=0

Using\:the\:Zero\:Factor\:Principle: if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

b=0,b-4=0

b=0,b=4

Therefore, the solutions are:

b=0,\:b=4

4 0
3 years ago
Read 2 more answers
PLEASE EXPLAIN ME THIS. IM BEGGING U
Natali5045456 [20]

Answer:

Step-by-step explanation:

Calculation

Divide your interest rate by the number of payments you'll make that year. ...

Multiply that number by your remaining loan balance to find out how much you'll pay in interest that month. ...

Subtract that interest from your fixed monthly payment to see how much in principal you will pay in the first month.

5 0
2 years ago
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