Question

Determine the value of n that makes the polynomial a perfect square trinomial. Then factor as the square of a binomial. Express numbers as integers or simplified fractions

Answer 1

Answer:

Step-by-step explanation:

$y^2-11y+n\\=(y-(11/2))^2+n-(11/2)^2$

So in order the trinomial a perfect square we need

$n-(11/2)^2 =0\\n= (11/2)^2\\n=\frac{121}{4}$

When n is equal to this number that we have

$y^2-11y+n = (y- (11/2))^2$