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Varvara68 [4.7K]
2 years ago
5

Consider the function below.

Mathematics
1 answer:
Brut [27]2 years ago
6 0

Answer:

Step-by-step explanation:

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Bob's Skate Shop had a profit of $3,563 during the month of August. The company models its profit using where x is the number of
CaHeK987 [17]

Answer:

The number of skateboard company sell during the month of August = 55

Step-by-step explanation:

We have given,

Profit function for Bob, P = x²+ 10x - 12

Bob's profit during August month is $3,563

That means, P = $3,563

We can use the profit formula given for Bob's profit:

P = x² + 10x - 12

Plug P =$3,563 in above formula.

i.e 3,563 = x² + 10x - 12

or 0 = x² + 10x -12 - 3,563

or 0 = x² + 10x - 3575

or x = 55, -65

Since number of skate boards can not be negative.

So we consider x= 55

Hence the number of skateboard company sell during the month of August = 55.

6 0
3 years ago
Chan jogs 10 miles a week. How many miles will she jog in 52 weeks?
igor_vitrenko [27]
520 miles because 52x10=520
4 0
3 years ago
Read 2 more answers
Find surface area of this regular pyramid
liq [111]

Answer:

189 ft²

Step-by-step explanation:

Here is the formula...

1/2 * 6 * 36 + 81

Hope this helps

7 0
2 years ago
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
Use the drop-down menus to complete the statements about factoring 14x2 + 6x – 7x – 3 by grouping. The GCF of the group (14x2 –
Yuliya22 [10]
14 x² + 6 x - 7 x - 3 =
= ( 14 x² - 7 x ) + ( 6 x - 3 ) =
= 7 x ( 2 x - 1 ) + 3 ( 2 x - 1 ) =
= ( 2 x - 1 ) ( 7 x + 3 )
Answer:
1.  GCF of the group ( 6 x - 3 ) is 3.
2.  The common binomial factor is 2 x - 1.
3.  The factored expression is:  ( 2 x - 1 ) ( 7 x + 3 ).
8 0
3 years ago
Read 2 more answers
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