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3 years ago

10

tessa is on the track team. for practise and exersise, she runs 2.25 miles each day. at the end of 14 days, how many total miles

will tessa have run

1 answer:

astra-53 [7]3 years ago

5 0

31.5 miles

If she runs 2.25 miles/day and she runs 14 days, you multiply 14*2.25

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Anna35 [415]

Answer:452.38934211693

Step-by-step explanation:

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2 years ago

The circular base of a cone has a radius of 5 centimeters. The height of the cone is 12 centimeters, and the slant height is 13

Iteru [2.4K]

Answer:

283 cm^2

Step-by-step explanation:

Solution:-

We have a cone with a circular base of radius r = 5 cm

The height of the cone is h = 12 cm

The slant height of the cone is L = 13 cm

We are to determine the surface area of the cone. The surface area of the cone is comprised of two parts:

Base Area : Circle

$A_1 = \pi r^2\\\\A_1 = \pi 5^2\\\\A_1 = 25\pi$

Curved Surface: conical

$A_2 = \pi * r*L\\\\A_2 = \pi * 5*13\\\\A_2 = 65\pi$

The total surface area of the cone can be written as ( A ):

$A = A_1 + A_2\\\\A = (25 + 65 )*\pi \\\\A = 90*(3.14) \\\\A = 282.7433 cm^2$

Answer: The surface area of the cone to nearest whole number would be 283 cm^2

4 0

3 years ago

neonofarm [45]

Answer: (see explanation)

Step-by-step explanation:

terms: 7, 2x, x4

leading coefficient: 7

constant term: 7

I'm sorry I'm unsure how to solve the last question.

8 0

2 years ago

HhH. The length of a rectangle is 5 ft more than the width.

Vaselesa [24]

Answer:

Easy, it's A.

5 more can be written as 5+ or +5. W is the width, so 5 more than the width is written as 5+w

5 0

3 years ago

Point T is the midpoint of JH. The coordinate of T is (0, 5) and the coordinate of J is (0, 2). The coordinate of H is:

aev [14]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&J&(~ 0 &,& 2~) 
% (c,d)
&H&(~ x &,& y~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left(\cfrac{x+0}{2}~~,~~\cfrac{y+2}{2} \right)=\stackrel{midpoint~T}{(0~,~5)}\implies 
\begin{cases}
\cfrac{x+0}{2}=0\\\\
\boxed{x=0}\\
------\\
\cfrac{y+2}{2}=5\\\\
y+2=10\\
\boxed{y=8}
\end{cases}$

6 0

3 years ago