If the graph crosses the x-axis and appears almost linear at the intercept, it is a single zero. If the graph touches the x-axis and bounces off of the axis, it is a zero with even multiplicity. If the graph crosses the x-axis at a zero, it is a zero with odd multiplicity. The sum of the multiplicities is the degree
Answer: y = -3(x +
)² +
,
,
<u>Step-by-step explanation:</u>
First, you need to complete the square:
y = -3x² - 5x + 1
<u> -1 </u> <u> -1 </u>
y - 1 = -3x² - 5x
y - 1 = -3(x² + ![\frac{5}{3}x](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B3%7Dx)
y - 1 + -3(
) = -3(x² +
+
)
↑ ↓ ↑
= ![(\frac{5}{3*2})^{2}](https://tex.z-dn.net/?f=%28%5Cfrac%7B5%7D%7B3%2A2%7D%29%5E%7B2%7D)
y - 1 -
= -3(x +
)²
y -
-
= -3(x +
)²
y -
= -3(x +
)²
y = -3(x +
)² +
Now, it is in the form of y = a(x - h)² + k <em>where (h, k) is the vertex</em>
Vertex =
,
Hello here is a solution:
Answer:
The answer is (2x+3)(5x+2)
Answer:
Bert has $45.
Step-by-step explanation:
I have no real strategy, except for that I used guess and check. How did I do this? Well, since I am in 5th Grade, I don't know algebra very well, so I made an organized chart and checked all the numbers that had to be a multiple and could be divided equally by 5, 3 and when a third of that number was subtracted by 6, it was a fifth of the orginal number. Thats how I got 45.
Checking this answer:
It is always important to check your answer after finishing the problem, so this is how I checked my answer:
1. 45 divided by 3 = 15
2. 15 - 6 = 9, and 9 is 1/5 of 45
Bert has $45.