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Aliun [14]
3 years ago
11

Please help Find the equation of this line. 1 a [?] x + [ ] y =

Mathematics
1 answer:
dezoksy [38]3 years ago
6 0
Start by finding the slope.

Pick 2 points on the line and find the “rise” and “run” between them.

To get from (0,3) to (4,0), you’d need to go “down 3” and “right 4”.

Since the slope is “rise over run” and a rise of “down 3” means a rise of “-3”, your slope is -3/4.

Next find the y-intercept: (0,3)
Use the 3 as your b-value for the slope-intercept form.

y=mx+b becomes y= -3/4 x + 3
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Answer:

im having the same problem

Step-by-step explanation:

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4 years ago
Math help !!! <br><br><br><br> I don't have answer choices so show the work please :)
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Find the equation of the line that passes through the point (7,5) and is perpendicular to the line 2x - 3y=6
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(7,5);\ \ \ \  2x - 3y=6 \ \ / subtract \ 2x \ from \ each \ side \\ \\-3y = -2x + 6\ \ /  divide \    each \term \ by \ (-3) \\ \\ y =  \frac{2} {3}x -2\\ \\ The \ slope \ is :m _{1} =  \frac{ 2}{3} \\ \\ If \ m_{1} \ and \ m _{2} \ are \ the \ gradients \ of \ two \ perpendicular \\ \\ lines \ we \ have \\\\\ m _{1}*m _{2} = -1

\frac{2}{3}\cdot m_{2}=-1\ \ / \cdot (\frac{3}{2})\\\\m_{2}=-\frac{3}{2}\\\\Now \ your \ equation \ of \ line \ passing \ through \ (7,5) would \ be: \\ \\ y=m_{2}x+b \\ \\5=-\frac{3}{2}\cdot 7  + b \\ \\ 5= -\frac{21}{2}+b\\ \\b=5+\frac{21}{2} \\ \\b= \frac{10}{2}+\frac{21}{2}\\ \\b= \frac{31}{2}\\\\b=15.5 \\ \\ y = -\frac{3}{2}x +15.5
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3 years ago
What is the factored form of the polynomial?
IceJOKER [234]

d.(x - 9) (x - 3)

Step-by-step explanation:

x² - 12x + 27 = 0

x² - 9x - 3x + 27 = 0

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5 0
4 years ago
P,W,R &amp; S form the vertices of a quadrilateral. PQR = 74 degrees
Zielflug [23.3K]

Answer:

∠ SPQ = 75°

Step-by-step explanation:

The sum of the 4 angles in a quadrilateral = 360°

Subtract the sum of the 3 angles from 360 for ∠ SPQ

∠ SPQ = 360° - (90 + 74 + 121)° = 360° - 285° = 75°

6 0
3 years ago
Read 2 more answers
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