The graphs that are density curves for a continuous random variable are: Graph A, C, D and E.
<h3>How to determine the density curves?</h3>
In Geometry, the area of the density curves for a continuous random variable must always be equal to one (1). Thus, we would test this rule in each of the curves:
Area A = (1 × 5 + 1 × 3 + 1 × 2) × 0.1
Area A = 10 × 0.1
Area A = 1 sq. units (True).
For curve B, we have:
Area B = (3 × 3) × 0.1
Area B = 9 × 0.1
Area B = 0.9 sq. units (False).
For curve C, we have:
Area C = (3 × 4 - 2 × 1) × 0.1
Area C = 10 × 0.1
Area C = 1 sq. units (False).
For curve D, we have:
Area D = (1 × 4 + 1 × 3 + 1 × 2 + 1 × 1) × 0.1
Area D = 10 × 0.1
Area D = 1 sq. units (True).
For curve E, we have:
Area E = (1/2 × 4 × 5) × 0.1
Area E = 10 × 0.1
Area E = 1 sq. units (True).
Read more on density curves here: brainly.com/question/26559908
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The answer is <span>length = 10 yd, width = 2 yd
proof
</span><span>The length of the playground is 5 times longer than its width, it means
l=5w, but 10= 2x5 so we can write l= 5w,
and Area = 20 =l x w = (5x2) x 2 =20</span>
Step-by-step explanation:
1= 118°+angle 1=180°
angle 1= 180°-118°=62°
angle 2=180°-135°=45°
angle 3=135°
I believe the first group would have 36 and the second group would have 12
14gallons=380miles
14/380=<span>0.03684210526gallons/mile
</span>
418*<span>0.03684210526=15.4gallons
</span>
or you could cross multiply
14gallons=380miles
x gallons=418miles

380x=5852
divide both sides by 380
x=15.4 gallons