The value of <em>x</em> where by exterior angles theorem, ∠DCO equals 2·x, 69° equals the sum of ∠DCO and x° is <em>x </em>= 23°
<h3>What is the exterior angles theorem?</h3>
The exterior angles theorem states that the exterior angle of a triangle is equal to the sum of the opposite interior angles.
The given parameters are;
Points on the circle are; ABCD
Straight lines = AOBE and DCE
Segment CO = Segment CE
∠AOD = 69°
∠CEO = x°
∠OCD = ∠ODC base angles of isosceles triangle
69° = ∠x° + ∠ODC exterior angle of a triangle
∠DOC = 180 - 2×∠ODC (Angle sum property of a triangle)
180 - 2×∠ODC + x° + 69° = 180° (Sum of angles on a straight line are supplementary)
x° + 69° - 2×∠ODC = 0
∠ODC = 2·x° (exterior angle of a triangle is equal to the sum of the opposite interior angles)
69° = x° + ∠ODC = x° + 2·x° = 3·x° (substitution property of equality)
69° = 3·x°
x = 69° ÷ 3 = 23°
Learn more about angles in a triangle here:
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I hope this helps you
if in 350 students are 14 students were absent
in 100 students are ?
?.350=100.4
?=400/360
?=1.14%
If you Just divided -11u and 44 by -11 u equals 4
-5/7 - (-6/7)z < -2/7
-5/7 + 6/7z < -2/7
6/7z = -2/7 + 5/7 = 3/7
z = 3/7 / 6/7 = 3/7 x 7/6 = 3/6 = 0.5
z = 0.5
Answer:2.8 m
Step-by-step explanation:
Given
The current fence height id 2 m
The gardener is told that he must increase the height of his fence by 40%
so new height is 
%
