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3 years ago

What is the solution of the system of linear equations graphed below ? PLEASE HELP

Mathematics

1 answer:

hjlf3 years ago

5 0

A linear equation is the equation of a straight line. The solution to the system of linear equations is infinitely many solutions.

There are two straight lines on the attached graph. The lines are:

The black line
The red line

And both lines lie on one another,

This means that, both lines have the following features:

The same slope
The same intercepts

When lines have the above features to be the same, it means the equations of both lines are the same.

And as such, the solution to the system is infinitely many solutions.

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Read 2 more answers

A number is divided into two parts, such that one part is 10 more than the other. If the two parts are in the ratio 5:3 find the

natta225 [31]

Answer:

See below

Step-by-step explanation:

Given the above information, we can make the first part to be;

First part = y + 10

Then,

Second part = y

y + 10 : y = 5 : 3

(y + 10) / y = (5) / (3)

Cross multiply,

3y + 30 = 5y

Collect like terms

5y - 3y = 30

2y = 30

y = 15

Therefore, substituting the value of y,

First part = y + 10

First part = 15 + 10

First part = 25

Second part = y

Second part = 15

Number = First part + Second part

Number = 25 + 15

Number = 40

3 0

3 years ago

Assume that θ is an acute angle in a right triangle satisfying the given conditions. Evaluate the 5 remaining trigonometric func

neonofarm [45]

Answer: See step by step. Replace the x with theta

Step-by-step explanation: Since sin is less than zero, and secant is positive. This means the trig values are in Quadrant 4.

We know that secФ=17/15. We need to find sin,cos,tan,csc, and cot.

We can find tangent by using the identity

$tan^{2} (x)+ 1=sec^{2} (x)$ where x is theta.

$tan^{2} (x)+1=\frac{289}{225}$

$tan^{2} (x)+\frac{225}{225} =\frac{289}{225}$

$tan^{2}(x)=\frac{64}{225}$

tan x= $\frac{8}{15}$ , Tangent in the fourth quadrant is negative so the answer is instead

$tan x= -\frac{8}{15}$

We can find cotangent by taking the recipocial of tan so

$cot=-\frac{15}{8}$

We can find cos by taking reciprocal of sec remeber that cosine is positive in 4th quadrant so the answer is

$cos =\frac{15}{17}$

We can find sin by doing quoteint identies.

$\frac{sin x}{cos x} =tan x$

$\frac{ sin x}{15/17} =-\frac{8}{15}$

$sin x= -\frac{8}{17}$

To find csc, take reciprocal of sine.

$csc=\frac{-17}{8}$

7 0

3 years ago

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kupik [55]

Answer:

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Step-by-step explanation:

Area= 150/360 (pi12^2)

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3 years ago