843 to the nearest 100

For every 36 minutes of sprinting, Scarlett earned 12 dollars for charity. To find the unit rate of this, I would first need to

grin007 [14]

Answer:

$1 every 3 minutes

Step-by-step explanation:

Cause every 36 minutes Scarlett earns $12 and if you divide 36 by 12 it will give 3 minutes which means she earns $1 per 3 minutes. You're right.

7 0

1 year ago

If AB = 13, BC = 9, and CA = 17, list the angles in order from smallest to largest.

Licemer1 [7]

A,C,B
This is the answer;BC,AB,CA

8 0

3 years ago

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago

I need help please! Not sure on this one.

TiliK225 [7]

Answer:

The scale factor is 0.5

Step-by-step explanation:

Figure A is 4 blocks wide and 4 blocks tall, Figure B is 2 blocks tall and 2 blocks wide, to get Figure B from Figure A you would need to scale it down by half (0.5)

3 0

2 years ago

Read 2 more answers

A bakery was about to sell fresh baguettes, and people formed a line outside to wait. While waiting for the bread to bake, every

Vikentia [17]

Answer:

The number of people standing in the original line is 22 people

Step-by-step explanation:

The information given are;

The number of baguettes that was shared by the people on the line = 85

The number of baguettes each person received = 1 each

Therefore;

The number of people that were finally on the line = 85

Let the number of people in the original line = X

Then each space between two people in X was filled by 1 new person of the first set of people who joined the line

Therefore;

The number of the first set of people who joined the line = The number of spaces between two count of people in X

Which gives;

The number of people who joined the line = X - 1

The new total number of people on the line = X + X - 1 = 2·X - 1

As time passed, a second set of people joined the line such that each space between the people waiting was filled with a new person (from the second set) who joined the line

Therefore, the number of people in the second set = Number of people waiting - 1

Which gives;

The number of people in the second set = 2·X - 1 - 1 = 2·X - 2

The total number of people on the line becomes 2·X - 1 + 2·X - 2 = 4·X - 3

The 85 baguettes is then able to go round (each) among the total number of people on the line

Therefore;

The total number of people on the line = The number of baguettes sheared

4·X - 3 = 85

4·X = 85 + 3 = 88

X = 88/4 = 22

Therefore;

The number of people standing in the original line = 22.

8 0

2 years ago