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pychu [463]
3 years ago
15

Please tell me how to solve this i just started geometry as a freshman and i don’t understand please!!!

Mathematics
2 answers:
aliya0001 [1]3 years ago
8 0

Answer:

80 degrees

Step-by-step explanation:

The whole angle EBD is 115 degrees, and angle DBG is 35 degrees, therefore

angle GBE is 115-35=80 degrees

Think about it like this, DBG and GBE need to add up to the angle measure of EBD, in other words 35 + GBE = 115

lord [1]3 years ago
4 0

Answer:

Step-by-step explanation:

<DBE = <DBG + <GBE

<DBE = 115                  Given

<DBG = 35                  Given

<GBE = ?

You have to know a couple of things before you start.

  • All the angles meet at B.
  • Notice B is the center letter.
  • the top given is the equation you need to solve the question.

115 = <GBE + 35                  Subtract 35 from both sides.

115 - 35 = <GBE

80 = <GBE

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Step-by-step explanation:10,000 cats

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2 years ago
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When 2x^2 - 20x + 49 = 19 is written in the form (x - p)^2 = q, what is the value of q? Show your work please.
Strike441 [17]
 = 2x^2 - 20x + 49 = 2(x^2 - 10x + 49/2) 

y= 2((x-5)^2 - 25 + 49/2) = 2((x-5)^2 - 1/2) = 2(x-5)^2 - 1 

q =5, r=-1, p=2 

Vertex = (q,r) = (5,-1)

hope it helps plz mark as brainliest
5 0
3 years ago
Please help me I need help
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Answer:

3.51

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i took 9.2 ÷ 4.14 to find how much they charged per oz. then i took 7.8 and multipled it by 45 cents per oz.

5 0
2 years ago
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3. At noon Lan is in his blue mini-van 300 km north of Makenna in her Bugatti. Lan heads south
LiRa [457]

Answer:

The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h

Step-by-step explanation:

At noon the location of Lan = 300 km north of Makenna

Lan's direction = South

Lan's speed = 60 km/h

Makenna's direction and speed = West at 75 km/h

The distance  Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km

The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km

The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km

Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.

By Pythagoras' theorem, we have;

s² = x² + y²

The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61

ds²/dt = dx²/dt + dy²/dt

2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt

2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900

ds/dt = 900/(2×30·√61) ≈ 1.92

The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h

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2 years ago
The diameter of a circle is 16 units. <br> What is the radius of the circle?
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Answer:

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2 years ago
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