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3 years ago

We want to find the zeros of this polynomial: p(x)= 3x^3 – 3x^2– 18x

Mathematics

2 answers:

bulgar [2K]3 years ago

3 0

Answer:

x=0 x=3 x=-2

Step-by-step explanation:

p(x)= 3x^3 – 3x^2– 18x

Factor out the greatest common factor, 3x

p(x)= 3x (x^2 – x– 6)

Factor inside the parentheses

What 2 numbers multiplies to -6 and adds to -1

-3*2 = -6

-3+2 = -1

p(x)= 3x (x-3)(x+2)

Setting the function equal to zero to find the zeros

0 = 3x (x-3)(x+2)

Using the zero product property

3x = 0 x-3 =0 x+2 =0

x=0 x=3 x=-2

madam [21]3 years ago

3 0

Answer:

x = -2, 0, 3.

Step-by-step explanation:

3x^3 – 3x^2– 18x = 0

First take out the GCF which is 3x:

3x(x^2 - x - 6) = 0

So one zero is 0 ( because 3x = 0).

x^2 - x - 6 = 0

(x - 3)(x + 2) = 0

x = -2, 3.

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Which equation represents the hyperbola in general form?

valina [46]

ANSWER

$9 {y}^{2} - 4 {x}^{2}- 36y + 16x - 16 = 0$

EXPLANATION

The standard equation of the hyperbola is

$\frac{ {(y - 2)}^{2} }{4} - \frac{ {(x - 2)}^{2} }{9} = 1$

We multiply through by 36 to obtain:

$9 {(y - 2)}^{2} - 4( {x - 2)}^{2} = 36$

We now expand to get,

$9( {y}^{2} - 4y + 4) - 4( {x}^{2} - 4x + 4) = 36$

Expand :

$9 {y}^{2} - 36y + 36 - 4 {x}^{2} + 16x - 16 = 36$

To get the general form, we equate everything to zero to get,

$9 {y}^{2} - 4 {x}^{2}- 36y + 16x - 16 = 0$

The correct choice is D.

7 0

3 years ago

Use the distance formula to find the distance, to the nearest tenth, from S(7, −1) to V(−1, 3).

34kurt

Answer: 8.9 units (choice C)

Explanation:

We plug $(x_1,y_1) = (7,-1) \text{ and } (x_2,y_2) = (-1,3)\\\\$ into the distance formula to get the following

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(7-(-1))^2 + (-1-3)^2}\\\\d = \sqrt{(7+1)^2 + (-1-3)^2}\\\\d = \sqrt{(8)^2 + (-4)^2}\\\\d = \sqrt{64 + 16}\\\\d = \sqrt{80}\\\\d \approx 8.94427\\\\d \approx 8.9\\\\$

4 0

2 years ago

In the given figure L1and L2 are two parallel sides . if the area of the rectangle PQRS is 60cm^2 then what is the area of the p

kiruha [24]

Answer:

Step-by-step explanation:

Believe it or not, the two areas are the same.

The base of the rectangle is PQ

The height of the rectangle is PS

Now look at the parallelogram.

The base is PQ

The height is PS

The area has to be the same in both cases. There is no other way to interpret what is happening.

4 0

3 years ago

Which pair of angles must be supplementary?<br> O 1 and 6<br> O 2 and 5<br> O 5 and 4<br> O Z6 and2

jeka57 [31]

Where’s the image? There has to be an image showing the angles to see which pairs of angles are supplementary.

7 0

3 years ago

What is the length of the conjugate axis? (y-2)^2/16 -(x+1)^2/144=1

aleksandr82 [10.1K]

Answer: 24

A hyperbola is the locus of a point in a plane which moves in the plane in such a way that the ratio of its distance from a fixed point in the same plane to its distance from a fixed line is always constant, which is always greater than unity.

the fixed point is called the focus and the fixed line is directrix and the ratio is the eccentricity.

The general equation for the vertical hyperbola is

[ (y-k)^2 / a^2 ] – [ (x-h)^2 / b^2 ] = 1

The conjugate axis of the vertical hyperbola is y = k

Length of the conjugate axis = 2b

According to the question k = 2, h = -1, a = 4, b = 12

Length of the conjugate axis = 2b = 2 * 12 = 24

Learn more about hyperbola here :

brainly.com/question/3351710

#SPJ9

7 0

2 years ago