When the function f(x) = 2x^n + ax^2 - 6 is divided by (x - 1), the remainder is -7 and when divided by (x + 3), the remainder i
s 129.
Calculate the value of "a" and "n" and hence write the polynomial function completely.
2 answers:
Answer:
Step-by-step explanation:
From the fact that the remainder is -7 after we divide by x -1 , then we know that f(1) = -7. But f(1) = 2 + a - 6.
So 2 + a - 6 = -7
a - 4 = -7
a = 4 - 7
a = -3.
Also we know that when divided by x + 3 the remainder is 129. Hence f( -3) = 129
129 = f(-3) = 2 (-3)^ n + (-3)(-3)^2 -6
129 = 2 (-3)^n -27 - 6
129 = 2 (-3)^n -33
129 + 33 = 2(-3)^n
162 = 2 (-3)^n
81 = (-3)^n
Hence n =4 and therefore f(x) = 2x^4 -3x^2 - 6.
Answer:
Step-by-step explanation:
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