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sweet-ann [11.9K]
3 years ago
15

Please help me ASAP i give brainliests and thanks :)

Mathematics
2 answers:
ohaa [14]3 years ago
5 0

Answer:

positive

Step-by-step explanation:

Firdavs [7]3 years ago
4 0

Answer:

Positive

Step-by-step explanation:

Since there are two x-intercepts, -2 and 2, there is a positive discriminant. If the parabola was below the x axis and opened downwards, the discriminant would be negative.

You might be interested in
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co
Ira Lisetskai [31]

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

The sample size is 103.

The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

df = 103-1 = 102

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have T = 2.63.

Now, we need to find the standard deviation of the sample. That is:

s = \frac{0.56}{\sqrt{103}} = 0.055

Now, we multiply T and s

M = T*s = 2.63*0.055 = 0.145

For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

5 0
3 years ago
A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n indepe
Finger [1]
The probability is 0.1458.

The probability is given by:

_{20}C_2(0.04)^2(1-0.04)^{20-2}
\\
\\=_{20}C_2(0.04)^2(0.96)^{18}=0.1458
5 0
3 years ago
2+square root x+4:10
Katyanochek1 [597]

Assuming the ':' means an = sign, 2\sqrt{x+4}=10 simplifies to 2\sqrt{x}=8

6 0
3 years ago
Find the zero of the following function: f(×)=(×-1)/(×-3)​
nlexa [21]

Answer:

\boxed{\sf \ \ x = 1 \ \ }

Step-by-step explanation:

Hello,

First of all we need to take x different from 3 as dividing by 0 is not allowed

then for x real different from 3

f(x)=0\\\\ \dfrac{x-1}{x-3}=0\\\\ x-1 = 0\\\\ x = 1

hope this helps

6 0
3 years ago
Read 2 more answers
Suppose that prices of recently sold homes in one neighborhood have a mean of $265,000 with a standard deviation of $9300. Using
Hatshy [7]

Answer:

Range  = (237100, 292900)

Step-by-step explanation:

Using Chebyshevs Inequality:

P(|X - \mu | \le k \sigma )\ge 1  -\dfrac{1}{k^2}= 0.889

1  -\dfrac{1}{k^2}= 0.889

\dfrac{1}{k^2}= 1- 0.889

\dfrac{1}{k^2}=0.111

k = \sqrt{\dfrac{1}{0.111}}

k \simeq 3

Thus, 88.9% of the population is within 3 standard deviation of the mean with the Range = μ  ±  kσ

where;

μ = 265000

σ = 9300

Range = 265000  ±  3(9300)

Range = 265000  ± 27900

Range =   (265000 - 27900, 265000 + 27900)

Range  = (237100, 292900)

3 0
2 years ago
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