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3 years ago

Can 4 cm, 5 cm and 6 cm be the sides of a right triangle?Justify.

Mathematics

1 answer:

balu736 [363]3 years ago

7 0

Answer:

See explanation below

Step-by-step explanation:

Can 4 cm, 5 cm and 6 cm be the sides of a right triangle?Justify.

For the side of the triangle to be right angled, the sum of the longest side must be equal to the sum of the squareof the other two sides

Given the sides 4cm, 5cm and 6cm

Longest side = 6cm

Square of longest side =6² =36cm

Sum of the square of other two sides = 4²+5²

= 16+25

= 41

Since 36≠41, hence the sides does not form a right angle.

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A cup of chocolate chips is 9 ounces a recipe calls for 3 and 3 4ths of ups how much ounces of chocolate are needed

Zinaida [17]

33.75 i think
Multiply 9 by 3 you get 27
Divide 9 by 4 and get 2.25
Multiply 2.25 by 3 which is 6.75
Add 27 and 6.75
33.75

5 0

3 years ago

Solve for x: |4x + 12| = 16

frosja888 [35]

<span>|4x + 12| = 16
As it is in modulus function, it could be either +ve or -ve
4x+12 = 16 OR 4x - 12 = 16
4x = 16-12 OR 4x = 16 + 12
4x = 4 OR 4x = 28
x = 4/4 OR x = 28/4
x = 1 OR x = 7

In short, Your Answer would be either 1 or 7

Hope this helps!</span>

3 0

4 years ago

Read 2 more answers

The accompanying data resulted from an experiment in which weld diameter x and shear strength y (in pounds) were determined for

saul85 [17]

Answer:

y hat = 2114.20 + 18.96x

Step-by-step explanation:

Given the least square regression model equation:

y hat = -959.00 + 8.60x

weld diameter x ; shear strength y (in pounds)

1 lb = 0.4536 kg

To express shear strength y in kilogram:

y is multiplied by 0.4536

(y hat × 0.4536) = -959.00 + 8.60x

Divide both sides by 0.4536

(y hat × 0.4536) / 0.4536= (-959.00 + 8.60x) / 0.4536

y hat = 2114.1975 + 18.959435x

y hat = 2114.20 + 18.96x

7 0

3 years ago

Factor both quadratic expressions. (x 4 + 5x 2 - 36)(2x 2 + 9x - 5) = 0

Sonbull [250]

So focusing on x^4 + 5x^2 - 36, we will be completing the square. Firstly, what two terms have a product of -36x^4 and a sum of 5x^2? That would be 9x^2 and -4x^2. Replace 5x^2 with 9x^2 - 4x^2: $x^4+9x^2-4x^2-36$

Next, factor x^4 + 9x^2 and -4x^2 - 36 separately. Make sure that they have the same quantity inside of the parentheses: $x^2(x^2+9)-4(x^2+9)$

Now you can rewrite this as $(x^2-4)(x^2+9)$ , however this is not completely factored. With (x^2 - 4), we are using the difference of squares, which is $a^2-b^2=(a+b)(a-b)$ . Applying that here, we have $(x+2)(x-2)(x^2+9)$ . x^4 + 5x^2 - 36 is completely factored.

Next, focusing now on 2x^2 + 9x - 5, we will also be completing the square. What two terms have a product of -10x^2 and a sum of 9x? That would be 10x and -x. Replace 9x with 10x - x: $2x^2+10x-x-5$

Next, factor 2x^2 + 10x and -x - 5 separately. Make sure that they have the same quantity on the inside: $2x(x+5)-1(x+5)$

Now you can rewrite the equation as $(2x-1)(x+5)$ . 2x^2 + 9x - 5 is completely factored.

<h3><u>Putting it all together, your factored expression is $(x+2)(x-2)(x^2+9)(2x-1)(x+5)=0$ </u></h3>

5 0

3 years ago

The median of the marks 10, 13, 3x-1, 3x+1, 18, 18 arranged in ascending order is

Lorico [155]

Answer:

a. Marks = 10, 13, 14, 16, 18, 18

b. mode = 18

c. Range = 8

Step-by-step explanation:

==>Given the following data set arranged in ascending order:

10, 13, 3x-1, 3x+1, 18, 18

Median = 15

==>Required:

a. Marks:

To get each marks, let's find the value of x since we know median to be 15.

10, 13, [3x-1, 3x+1], 18, 18

Our median in this even number of data set would be the average of the 2 middle values which would give us 15.

Thus, we have:

[(3x-1) + (3x+1)] ÷ 2 = 15

[3x-1 + 3x+1] ÷ 2 = 15

[3x+3x-1+1] ÷ 2 = 15

6x/2 = 15

Multiply 2 by both sides

6x = 30

Divide 6 by both sides

x = 5

Now let's plug in the value of x to get out marks:

10, 13, 3(5)-1, 3(5)+1, 18, 18

10, 13, 14, 16, 18, 18

b. Mode is the most appeared data value, which is 18

c. Range is the difference between the highest and lowest value = 18 - 10 = 8

5 0

3 years ago