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inysia [295]
2 years ago
9

Can 4 cm, 5 cm and 6 cm be the sides of a right triangle?Justify.

Mathematics
1 answer:
balu736 [363]2 years ago
7 0

Answer:

See explanation below

Step-by-step explanation:

Can 4 cm, 5 cm and 6 cm be the sides of a right triangle?Justify.

For the side of the triangle to be right angled, the sum of the longest side must be equal to the sum of the squareof the other two sides

Given the sides 4cm, 5cm and 6cm

Longest side = 6cm

Square of longest side =6² =36cm

Sum of the square of other two sides = 4²+5²

= 16+25

= 41

Since 36≠41, hence the sides does not form a right angle.

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If f(x)=5x^3 and g(x)=x+1, find (f•g)(x)
alukav5142 [94]

Hello from MrBillDoesMath!

Answer:

5 x^3 + 15 x^2 + 15 x + 5 , none of the provided choices

Discussion:

f(x) = 5 x^3

g(x) = x+ 1  

=>

(f•g)(x) =

f(g(x)) =

f(x+1) =

5 * (x+1)^3 =

5 x^3 + 15 x^2 + 15 x + 5

which is none of the provided answers.

Thank you,

MrB

5 0
3 years ago
Which graph corresponds to the following inequality? A. B. C. D.
zlopas [31]
I can see the question but if you add a picture maybe i’ll understand it a little more
6 0
2 years ago
4125 x 10 to the 3rd power
Kobotan [32]

In standard form, it would look like this:

4125 * 1000

This would be 4,125,000

4 0
3 years ago
Read 2 more answers
A used car dealer sells SUVs and cars. Of all the vehicles, 90% are cars. Of all the vehicles 40% are red cars. What is the prob
AleksAgata [21]

Answer:

44.4%

Step-by-step explanation:

To calculate this, we proceed as follows.

we use the probability equation below;

P(A|B) = P(A and B) / P(B)

Applying the above to the scenario at hand;

P(red | car) = P(red and car) / P(car)

P(red and car) = 40% or simply 40/100 = 0.4

P(car) = 90% = 90/100 = 0.9

P(red | car) = 0.4/0.9

P(red | car) = 0.4444 which is = 44.44% ; to the nearest tenth of a percent = 44.4%

4 0
3 years ago
Can someone help me with this problem://
fiasKO [112]

You can simply collect terms, subtract the constant and divide by the x-coefficient. It is generally considered easier to do those steps if you eliminate fractions first (multiply by 12).

Multiply by 12

... 4(x -1) +3(x +5) = 6

... 4x -4 +3x +15 = 6 . . . . . eliminate parentheses

... 7x +11 = 6 . . . . . . . . . . . .collect terms

... 7x = -5 . . . . . . . . . . . . . . subtract the constant 11

... x = -5/7 . . . . . . . . . . . . . divide by the x-coefficient

_ _ _ _ _ _ _

Here it is the other way.

... x(1/3 +1/4) +(-1/3 +5/4) = 1/2

... (7/12)x + 11/12 = 1/2 . . add the fractions to finish collecting terms

... x + 11/7 = 6/7 . . . . . . . multiply by 12/7

... x = -5/7 . . . . . . . . . . . subtract 11/7

At the third step here, you could subtract 11/12 before doing the multiply. You get the same answer, but you have to do the extra conversion of 1/2=6/12.

8 0
3 years ago
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