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inysia [295]
2 years ago
9

Can 4 cm, 5 cm and 6 cm be the sides of a right triangle?Justify.

Mathematics
1 answer:
balu736 [363]2 years ago
7 0

Answer:

See explanation below

Step-by-step explanation:

Can 4 cm, 5 cm and 6 cm be the sides of a right triangle?Justify.

For the side of the triangle to be right angled, the sum of the longest side must be equal to the sum of the squareof the other two sides

Given the sides 4cm, 5cm and 6cm

Longest side = 6cm

Square of longest side =6² =36cm

Sum of the square of other two sides = 4²+5²

= 16+25

= 41

Since 36≠41, hence the sides does not form a right angle.

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7 0
3 years ago
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Please help me on this problem
Orlov [11]

Answer:

The Proof with Figure, Statement and Reasons is given below.

Step-by-step explanation:

Given:

∠DAF ≅ ∠EBF,

DF ≅  FE

Prove:

Δ ADF ≅ Δ BFE

Proof:

       Statements                                 Reasons

a. ∠DAF ≅ ∠EBF       ...........................Given

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6 0
3 years ago
What is the Value of f(6) if f(x)=2x-11
il63 [147K]
The answers are
f
o
g
(
x
)
=
−
2
x
+
23
and
g
o
f
(
x
)
=
−
2
x
+
5

Explanation:
f
(
x
)
=
−
2
x
+
11

g
(
x
)
=
x
−
6

f
o
g
(
x
)
=
f
(
g
(
x
)
)
=
f
(
x
−
6
)
=
−
2
(
x
−
6
)
+
11

=
−
2
x
+
12
+
11
=
−
2
x
+
23

g
o
f
(
x
)
=
g
(
f
(
x
)
)
=
g
(
−
2
x
+
11
)
=
−
2
x
+
11
−
6

=
−
2
x
+
5

I think that the equations speak by themselves.
Of course,
f
o
g
(
x
)
≠
g
o
f
(
x
)
3 0
2 years ago
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