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2 years ago

7

Solve: |x+2|−1≥5. Write your solution in interval notation.

1 answer:

AlekseyPX2 years ago

6 0

nswer:

Step-by-step explanat

|x+2| - 1 ≥ 5

 |x+2| ≥ 5+1

 |x+2| ≥ 6

 x+2 ≥ 6 hoặc x+2 ≤ -6

+ với x+2 ≥ 6  x ≥ 6 – 2  x ≥ 4

+ với x+2 ≤ -6  x ≤ -6 – 2  x ≤ -8

(-∝;-8)∪(4;+∝)

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Convert 5 miles to meters round to the nearest meter

m_a_m_a [10]

Answer:

8047

Step-by-step explanation:

Five miles is equivalent to 8046.72

5 miles = 8046.72

Look at the decimal number and notice that its closer to 100 than 0

So 8046.72 is rounded to 8047

Hope this helps <3

5 0

3 years ago

What is the horizontal asymptote of f(x)=-2x/x+1<br> A.-2<br> B.-1<br> C.0<br> D.1

Mrrafil [7]

A horizontal asymptote of a function f(x) is given by y = lim f(x) as x --> ∞ and x --> –∞. In this case,
$\lim_{x \to \infty} \frac{-2x}{x+1} = \lim_{x \to \infty} \frac{-2x}{x(1+ \frac{1}{x} )}\\
=\lim_{x \to \infty} \frac{-2}{1+ \frac{1}{x} }\\
= -2
$

Thus, the horizontal asymptote of f(x) is y = –2.

7 0

3 years ago

Read 2 more answers

aticengleSidesourcesActivitiesClassify the following triangle. Check all that apply.11.9132eA. equilateralB. obtusen C. rightD.

Anuta_ua [19.1K]

The triangle is obtuse and scalene.

7 0

2 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

HELLO. I NEED HELP ON A HANDFUL OF QUESTIONS. PLEASE HELP.

galben [10]

Question 7: $3945

78,900÷100×5= 3,945

or 789,00×0.05= $3,945

Question 8: I think it may be $675.46 ( but I'm not sure)

$1010 is her annual insurance premium so to find one month we need to divide $1010 by 12

$1010÷12= $84.20

also her annual real estate tax is $938 and to find one month we need to divide this by 12 as well.

$938÷12=$78.20

and in order to find out her combined monthly payment we need to add them all together

$513.12+$84.16+$78.16= $675.46

Question 9: is False

Question 10: I don't know

Hope this helps

5 0

3 years ago