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maria [59]
3 years ago
7

Solve: |x+2|−1≥5. Write your solution in interval notation.

Mathematics
1 answer:
AlekseyPX3 years ago
6 0

nswer:

Step-by-step explanat

|x+2| - 1 ≥ 5

  |x+2|  ≥ 5+1

 |x+2|  ≥ 6

 x+2 ≥ 6 hoặc x+2 ≤ -6

+ với x+2 ≥ 6  x ≥ 6 – 2   x ≥ 4

+ với x+2 ≤ -6  x ≤ -6 – 2  x ≤ -8

(-∝;-8)∪(4;+∝)

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