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maria [59]
3 years ago
7

Solve: |x+2|−1≥5. Write your solution in interval notation.

Mathematics
1 answer:
AlekseyPX3 years ago
6 0

nswer:

Step-by-step explanat

|x+2| - 1 ≥ 5

  |x+2|  ≥ 5+1

 |x+2|  ≥ 6

 x+2 ≥ 6 hoặc x+2 ≤ -6

+ với x+2 ≥ 6  x ≥ 6 – 2   x ≥ 4

+ với x+2 ≤ -6  x ≤ -6 – 2  x ≤ -8

(-∝;-8)∪(4;+∝)

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The ten's digit of a two digit number is 1 more than 4 times the units' digit. if 63 is subtracted from the number, the order of
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Let x be the digit in the tens place and y be the digit in the ones place.
so, the digit is xy
<span>
The ten's digit of a two digit number is 1 more than 4 times the units' digit.
</span>x = 4y + 1

<span>63 is subtracted from the number, the order of the digits is reversed
</span>10x + y - 63 = 10y + x
9x - 9y = 63

x = 4y + 1 ------------ (1)
9x - 9y = 63  ---------- (2)

Sub (1) into (2)
9(4y + 1) - 9y = 63
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Jack made 50% more smoothies than yesterday. If he made 30 smoothie today how many did he make yesterday?
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3 years ago
Two thirds of a number decreased by 27 is at least 9
Vitek1552 [10]

Answer:

The mathematical statement can be written as follows

\frac{2}{3}x-27\geq9

which has solution as

⇒  x\geq54

Step-by-step explanation:

Given:

Two thirds of a number decreased by 27 is at least 9.

This statement can be transformed into a mathematical statement.

Taking the unknown number as x and putting the inequality \geq9 as the result is at least 9.

So, we have

\frac{2}{3}x-27\geq9

Adding 27 both sides

\frac{2}{3}x-27+27\geq 9+27

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Dividing both sides by 2.

\frac{2x}{2}\geq\frac{108}{2}

∴ x\geq54

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3 years ago
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