Answer:
Step-by-step explanation:
Supposing 30 days in the month of May (which is not always same in every year),we have,
S= Sample Space
n(S)=total days in a year=365 days
n(E)=no of favourable events
= no of days in the month of May=30 days
Then the probability is of favourable events is,
P(E)=n(E)/n(S)=30/365=6/73
Now,the probability that the birthday is not in May is,
P'(E) =1-6/73=67/73 ANS!!!
<span>x - 13 ≥ 15
x </span>≥ 28
hope that helps
∆ABC=∆DEF
AB=DE –>String
BC=EF–> Rib
m<C=m<F=90° –>List
AC=DF
So m<A=m<D=35 (It is not clear whether the number is 35 or 36, but the same number)
Your answer would be
True
Hope I helped!
