Hello!
We have:
X^2 + 2x-15 = 0
Where:
a = 1
b = 2
c = -15
Delta = b^2 -4.a.c
D = 2^2 - 4.1.(-15)
D = 4 + 60
D = 64
We know,
x = [ -b+/-Raiz(delta)]/2a
x = [ -2 +/- Raiz(64)]/2
x = [-2 +/- 8]/2
Then,
x' = (-2-8)/2 <=> -5
And
x" = (-2+8)/2 <=> 3
For the first equation, you start at 0 and go by 30. The second one you start at 125 then go up gradually by 20 like you did for the first equation. Hope it helped
Hey there!!
Distance formula :
Coordinates given :
( 0,1 ) and ( 2,-3 )
( y2 = -3 ; y1 = 1 ) ( x2 = 2 ; x1 = 0 )
Plugging in the values :
... 
... 
... 
... 
... 
×
... 2 units is the distance.
Hope my answer helps!!
I think the answer is <span>6.418 x 10^<span>3. Not sure if you're asking for the picture or the text...</span></span>
