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3 years ago

24k to the power of 9 over 6k to the power of 6

Mathematics

2 answers:

Brums [2.3K]3 years ago

6 0

Answer:

0 m30 kg15 s-30 K-15

Step-by-step explanation:

that should be the answer

nexus9112 [7]3 years ago

5 0

Here is the awnser have a great day

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at the city museum child admission is $5.10 and adult admission is $9.60. on thursday 132 tickets were sold for a total sale of

Bad White [126]

C + a = 132.....a = 132 - c
5.10c + 9.60a = 898.20

5.10c + 9.60(132 - c) = 898.20
5.10c + 1267.20 - 9.60c = 898.20
5.10c - 9.60c = 898.20 - 1267.20
-4.50c = - 369
c = -369/-4.50
c = 82 <=== child tickets sold

5 0

3 years ago

Work out total surface area of pyramid

Agata [3.3K]

You would need to know the dimensions of the pyramid and wether it was triangle or square bottomed

7 0

3 years ago

Point K on the number line shows Kelvin's score after the first round of a quiz: A number line is shown from negative 10 to 0 to

Ierofanga [76]

Answer:

The correct option is;

3 + (-9) = -6, because -6 is 9 units to the left of 3

Step-by-step explanation:

The given information are;

Kelvin's score after the first round is shown at point K on the number line

The range of numbers on the number line = -10 to +10

The position of point K after the first round = +3

The number of points Kevin lost in the second round = 9 points

Therefore, Kevin's cumulative score = +3 - 9 = -6

Therefore, the expression that shows how many total points he has at the end is of round 2 = 3 + (-9) = -6, because -6 is 9 units to the left of 3.

7 0

3 years ago

Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1

kari74 [83]

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

Background of the Discriminant

The discriminant $b^2-4ac$ applies to quadratic equations when they are organised in standard form: $ax^2+bx+c=0$ .

All quadratic equations can be solved with the quadratic formula: $x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}$ .

When $b^2-4ac$ is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

Solving the Problem

$3x^2+5x=-1$

We're given the above equation. It hasn't been organised completely in $ax^2+bx+c=0$ , but we can change that by adding 1 to both sides to make the right side equal to 0:

$3x^2+5x+1=0$

Now that we can identify the values of a, b and c, we can plug them into the discriminant:

$D=b^2-4ac\\D=(5)^2-4(3)(1)\\D=25-4(3)(1)\\D=25-12\\D=13$

Therefore, because the discriminant is positive, the equation has two real, distinct solutions.

I hope this helps!

4 0

3 years ago

What is the perimeter of this red polygon ??

noname [10]

Answer:

Step-by-step explanation:

4+4+4+2+2+3+3+4=26

How I found the Other lengths, REASON :

Other pair of lengths are tangents to circle from a single point so their lengths are equal.

5 0

3 years ago