24k to the power of 9 over 6k to the power of 6
2 answers:
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Answer:
1) Option c) is correct ie., 5 real and o non-real
2) Option b) is correct ie., (4, ,
, 2,2)
Step-by-step explanation:
Given polynomial function is
To find zeros equate f(x) to zero ie.,
By synthetic division
| 1 0 -3 0 -2
-1 | 0 -1 1 2 2
|_________________
1 -1 -2 2 0
Therefore x=-1 is a zero
| 1 -1 -2 2
1 | 0 1 0 2
|___________________
1 0 -2 0
x=1 is the zero
and
Option c) is correct ie., 5 real and o non-real
2) Given polynomial function is
To find zeros equate f(x) to zero ie.,
(or)
or
Therefore x=4, of multiplicity of 2 and x=2 multiplicity of 2
Option b) is correct ie., (4, ,
, 2,2)