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qaws [65]
2 years ago
7

Find the arithmetic mean of 14 and 29.

Mathematics
2 answers:
Romashka [77]2 years ago
8 0

Answer:

Arithmetic mean =( 14+29 )/2

A.M = 21.5

Step-by-step explanation:

<h2>Hope it helps you</h2>
kotykmax [81]2 years ago
5 0

Answer:

Please mark Brainliest

Step-by-step explanation:

\frac{14+29}{2}

Is the mean

Before I calculate, I will explain WHY the fraction above appeared

What is the mean and how to find it?

This is how:

We add all the numbers in the dataset and then divide by the amount of numbers in the given dataset.

Something you might think:

<em>What are you talking about?!</em>

The fraction above shows everything.

There are 2 numbers in the dataset, so we divide by 2.

14+29=43/2=21.5

Hope this helps!

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Can someone please help me I’m not getting it
mr_godi [17]
The answer to the question is (-3,3)

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Langston has $45$ greeting cards. He gives $18$ of the cards to his friends. What percent of his greeting cards does he give to
dalvyx [7]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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Assume that a sample is used to estimate a population proportion p. find the margin of error e that corresponds to the given sta
Leno4ka [110]

Let p be the proportion. Let c be the given confidence level , n be the sample size.

Given: p=0.3, n=1180, c=0.99

The formula to find the Margin of error is

ME = z _{\alpha/2}  \sqrt{\frac{p*(1-p)}{n}}

Where z (α/2) is critical value of z.

P(Z < z) = α/2

where α/2 = (1- 0.99) /2 = 0.005

P(Z < z) = 0.005

So in z score table look for probability exactly or close to 0.005 . There is no exact 0.005 probability value in z score table. However there two close values 0.0051 and 0.0049 . It means our required 0.005 value lies between these two probability values.

The z score corresponding to 0.0051 is -2.57 and 0.0049 is -2.58. So the required z score will be average of -2.57 and -2.58

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For computing margin of error consider positive z score value which is 2.575

The margin of error will be

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ME = 0.0342

The margin of error is 0.0342

7 0
3 years ago
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