All categories

3 years ago

Need help with this asap

Mathematics

1 answer:

valentina_108 [34]3 years ago

6 0

Answer: the first one is exponential and the second one is function

You might be interested in

Help me please thank you so much

wel

Answer: Susan, sam forgot to flip the signs while dividing a negative number.

6 0

3 years ago

Clarice Sloan is a shift supervisor for Ace

Igoryamba

The net pay is the amount left after taxes and deductions have been removed from the gross pay.

Her monthly gross pay is: $4111.93

The deductions are:

$\mathbf{FIT = \$102}$

$\mathbf{SIT = 3.2\%}$

$\mathbf{CIT = 1.8\%}$

Let her gross pay be x.

So, we have:

$\mathbf{Net = x - FIT - x \times SIT - x \times CIT}$

So, we have:

$\mathbf{3804.33 = x - 102 - x \times 3.2\%- x \times 1.8\%}$

Express percentage as decimals

$\mathbf{3804.33 = x - 102 - x \times 0.032- x \times 0.018}$

$\mathbf{3804.33 = x - 102 - 0.032x - 0.018x}$

Add 102 to both sides

$\mathbf{3906.33 = x - 0.032x - 0.018x}$

$\mathbf{3906.33 = 0.95x}$

Divide both sides by 0.95

$\mathbf{4111.93 = x}$

Rewrite as:

$\mathbf{x = 4111.93 }$

Hence, her monthly gross pay is: $4111.93

Read more about gross and net pay at:

brainly.com/question/8952173

4 0

3 years ago

7/5=10.5/x<br><br> Help plz

Natasha_Volkova [10]

7.5. 10.5*5 and divide that by 7

6 0

3 years ago

Read 2 more answers

In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i

PilotLPTM [1.2K]

Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,

was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

$\bf \displaystyle \int -32\cdot dt\implies -32t+C
\\\\\\
\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}
\\\\\\
-32(0)+C=0\implies C=0\implies \boxed{v(t)=-32t}
\\\\\\
\textit{now to get the positional s(t)}
\\\\\\
\displaystyle \int -32t\cdot dt\implies -16t^2+C
\\\\\\
\textit{the initial \underline{position} was 400ft away at 0secs}
\\\\\\
-16(0)^2+C=400\implies C=400\implies \boxed{s(t)=-16t^2+400}$

when will it reach the ground level? let's set s(t) = 0

$\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2
\\\\\\
25=t^2\implies \boxed{5=t}$

part B) check the picture below

5 0

3 years ago

Help me with these questions

egoroff_w [7]

For number 6 it's 30 x 45

5 0

3 years ago