The inverse of the matrix
is the matrix
.
The inverse of a matrix A is calculated by the formula:
A' = (1/|A|)(Adj A),
where A' represents the inverse of matrix A,
|A| represents the determinant value of matrix A, and
Adj A represents the Adjoin matrix of matrix A.
So, to calculate the inverse of the matrix
, we will first calculate its Adj.
Adj =
=
.
Now, we calculate |A| = 11*(-1) - (-5)*3 = -11 + 15 = 4.
Therefore A' = (1/|A|)(Adj A),
or, A' =
,
or, A' =
.
Therefore, the inverse of the matrix
is the matrix
.
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Does 0.007/10=0.07
true or false?
Answer:
NO if you wanted to get 0.07 you would have to multiply not divide.
Step-by-step explanation:
0.007/10=0.0007
Answer:
Yes you can form a triangle with those angles
Step-by-step explanation:
Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.
Zigmanuir [339]
The mean is the average.
So, to find the mean you want o add up all of the numbers and then divide by the number of numbers.
49 + 49 + 54 + 55 + 52 + 49 + 575 = 363
363 / 7 = 51.85
Rounded to 52
For the median you want o line all of your number up from least to greatest and then find the middle number.
49,49,49,52,54,55,55
Your median is 52
The mode is the number that is listed most often
49 is listed 3 times
54 is listed 1 time
52 is listed 1 time
55 is listed 2 times
So, your mode is 49
A. <u>False.</u> The range of
is the set of values it can produce. In the table,
produces values from
to
. However, the range of all real numbers is all rational numbers, basically from
to
, not just a few numbers in-between. So, the range of
is not all real numbers.
B. <u>True.</u> Looking at the table, when
,
. This is another way of saying that
, which is what B is saying.
C. <u>True.</u> The domain of
is the set of values of
that produce some output in
. Looking at the table, all of the
values listed on it are in the set
, which is what C is saying.
D. <u>False.</u> Looking at the table, when
,
. This is another way of saying that
, which is <em>not </em>what B is saying.