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Galina-37 [17]
3 years ago
13

Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.

Mathematics
1 answer:
Zigmanuir [339]3 years ago
4 0
The mean is the average.
So, to find the mean you want o add up all of the numbers and then divide by the number of numbers.

49 + 49 + 54 + 55 + 52 + 49 + 575 = 363
363 / 7 = 51.85
Rounded to 52

For the median you want o line all of your number up from least to greatest and then find the middle number.

49,49,49,52,54,55,55

Your median is 52

The mode is the number that is listed most often

49 is listed 3 times
54 is listed 1 time
52 is listed 1 time
55 is listed 2 times

So, your mode is 49




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What is 2 1/6 - 3 4/9?
vodomira [7]
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2 1/6 - 3 4/9
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Simplify the expression.
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5(8x - 10) - 10x + 25(8x - 10) - 10x + 2
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5 0
2 years ago
Express 10 3/2 in simplest radical form
Alborosie

Answer:

23/2

Step-by-step explanation:

first turn the mixed number into a fraction:

2*10=20

20+3=23

so, we get 23/2

7 0
3 years ago
Find the larger of two consecutive integers if the larger is 149 less than twice the smaller.
snow_tiger [21]

Answer:

151

Step-by-step explanation:

Let x = the smaller integer and y = the larger integer.

We have two conditions:

(1)   x + 1 = y

(2)       y =  2x - 149      Substitute (1) into (2)

    x + 1 = 2x - 149        Add 150 to each side

x + 150 = 2x                 Subtract x from each side

        x = 150                Substitute into (1)

150 +1 = y

       y = 151

The larger integer is 151.

<em>Check: </em>

(1) 150 + 1 = 151

          151 = 151

(2)       151 = 2×150 -149

          151 = 300 -149

          151 = 151

4 0
3 years ago
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