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3 years ago

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Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.

1 answer:

Zigmanuir [339]3 years ago

4 0

The mean is the average.
So, to find the mean you want o add up all of the numbers and then divide by the number of numbers.

49 + 49 + 54 + 55 + 52 + 49 + 575 = 363
363 / 7 = 51.85
Rounded to 52

For the median you want o line all of your number up from least to greatest and then find the middle number.

49,49,49,52,54,55,55

Your median is 52

The mode is the number that is listed most often

49 is listed 3 times
54 is listed 1 time
52 is listed 1 time
55 is listed 2 times

So, your mode is 49

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2 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

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Answer:

a) Q(-2,1) is false

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Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

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Here $-2$ that is $x$ satisfied. Then

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That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

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Here $-5$ that is $x$ this condition is satisfied.

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This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

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d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

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2 years ago

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3 years ago

Read 2 more answers

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Phoenix [80]

Answer:

(8,21)

Step-by-step explanation:

Since both equations equal y, set both equaitions equal to each other

and solve for x

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x=8

Substitute x=8 into either equation to solve for y

y=4(8)-11

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3 years ago