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arsen [322]
3 years ago
6

The diagonals of a rhombus are 30cm and 16cm. Find its area, the length of a side and its perimeter.​

Mathematics
2 answers:
Bad White [126]3 years ago
8 0

Answer:

Step-by-step explanation:

\large \boldsymbol {} \tt Formulas : \\\\d_1^2+d_2^2=4a^2 \\\\S=\dfrac{1}{2} d_1d_2 \\\\  \ where  \ S \  is  \ the \  area \  of \  the  \ rhombus  \ ;\\\\\  and \  d_1  \ and \ d_2 \  are \ its \ diagonals \ ; \ and \  a \ ,  \\\\\\  respectively, \  is\  the \ side \  of\  the rhombus \\\\ then : \\\\ 4a^2=16^2+30^2 \\\\ 4a^2=1156 \\\\a^2=289 \\\\a=17  \ \ then  \  P=4a=17*4=\boldsymbol {68} \\\\  \tt S=\dfrac{1}{2} \cdot 30 \cdot 16 =\boldsymbol {240 } \\\\ Answer : S=240 \ ; a=17  \ ;  \  P=68  \ ;

Free_Kalibri [48]3 years ago
5 0

Answer:

Area = 1/2 × product of diagonalsso area = 1/2 × 30 ×16 = 240 cm²

also diagonals bisect each other at right angles so 1/2×30= 15cm,, 1/2× 16 = 8cm

therefore by pythagoras theorem,

{15 }^{2}+ {8}^{2}= {side}^{2}\sqrt{289 = side}

side = 17

Perimeter = 4×17 =68 cm.

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