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Artemon [7]
3 years ago
8

The number 56 can be written as 2to the power of m x n, where m and n are prime numbers.

Mathematics
1 answer:
Sholpan [36]3 years ago
7 0

9514 1404 393

Answer:

  4. m = 3, n = 7

  5. a) 2.0272; b) 72.4; c) 372

Step-by-step explanation:

4. 56 = 8×7 = 2^3 × 7

Comparing to 2^m × n, we see that m=3, n=7.

__

5. It's all about scale factors. One way to work this problem is to write all of the numbers in terms of the numbers of the original "given."

a) 0.724 × 2.8 = (724×10^-3) × (28×10^-1) = 20272×10^-4

  0.724 × 2.8 = 2.0272

__

b) 202.72 ÷ 2.8 = (20272×10^-2) ÷ (28×10^-1) = 724×10^(-2-(-1)) = 72.4

  202.72 ÷ 2.8 = 72.4

__

c) 20272 ÷ 56 = (20272 ÷ 28) ÷ 2 = 724 ÷ 2 = 362

  20272 ÷ 56 = 372

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Use Algorithm 7 to schedule the largest number of talks in a lecture hall from a proposed set of talks, if the starting and endi
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Answer:

If we arrange the talks from the lowest starting time to the highest ending time we get total of 11 talks.

using algorithm 7 we get answer   (1) - (3) - (6) - (9)   the largest number of talks scheduled.

Step-by-step explanation:

arranging the talks from lowest starting time to the highest ending time.

thus,

  1. 9:00 a.m. and 9:45 a.m.
  2. 9:30 a.m. and 10:00 a.m.
  3. 9:50 a.m. and 10:15 a.m.
  4. 10:00 a.m. and 10:30 a.m.
  5. 10:10 a.m. and 10:25 a.m.
  6. 10:30 a.m. and 10:55 a.m.
  7. 10:15 a.m. and 10:45 a.m.
  8. 10:30 a.m. and 11:00 a.m.
  9. 10:45 a.m. and 11:30 a.m.
  10. 10:55 a.m. and 11:25 a.m.
  11. 11:00 a.m. and 11:15 a.m.

we start from the earliest time as

9:00 a.m. and 9:45 a.m which is (1).

After the talk is finished we pick the nearest time for another talk which starts at

9:50 a.m. and 10:15 a.m which is (3).

After this talk we again pick the nearest time for another talk which becomes

10:30 a.m. and 10:55 a.m which is (6).

and lastly

10:45 a.m. and 11:30 a.m which is (9).

Note: we didn't choose other times because we cannot talk at 2 or 3 places at the same time. so we pick another when one talk is finished.

thus the answer is (1) - (3) - (6) - (9) as the largest number of talks scheduled.

4 0
4 years ago
2.50=?%...............................
k0ka [10]
2.50 would be 25% out of 100%
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Will give alot of points!
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4 years ago
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