Answer:
C
Step-by-step explanation:
2*4*6
2*4=8
8*6=48.
Answer:
You should expect to find the middle 98% of most head breadths between 3.34 in and 8.46 in.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
In what range would you expect to find the middle 98% of most head breadths?
From the: 50 - (98/2) = 1st percentile.
To the: 50 + (98/2) = 99th percentile.
1st percentile:
X when Z has a pvalue of 0.01. So X when Z = -2.327.
99th percentile:
X when Z has a pvalue of 0.99. So X when Z = 2.327.
You should expect to find the middle 98% of most head breadths between 3.34 in and 8.46 in.
.55km x 5 days = 2.75km
.55km x 1.4 = .77km x 2 = 1.54km
2.75km + 1.54km = 4.29km in one week.
Answer:
I think that the selected answer is correct
Step-by-step explanation: