Answer: Down there there is an image with the correct answer and step by step
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Answer:
7/8 < 15/16
Step-by-step explanation:
Get a common denominator of 16
7/8 *2/2
14/16
14/16 < 15/16
so 7/8 < 15/16
Answer:
p = 14/4
Step-by-step explanation:
-4p+9=-5
-4p = -14
p = 14/4
No, 2 of the 5x7 would actually take up. 10x14
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5